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kykrilka [37]
3 years ago
10

Question 5- Please help. Using a piece of pizza explain what arc length and area of the sector mean in two to three sentences.

Mathematics
1 answer:
pickupchik [31]3 years ago
3 0

Answer:

You'd have to look at the size of the pizza and then measure the size of the arc for each slice. The slice of pizza is how many topping is on it. The sector is how much pizza you are consuming from the center to the crust. The arc is the crust around the pizza.

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What is 5x-7(x+1)=9<br> Thanks for the help
mylen [45]

Answer:

x = -8

Step-by-step explanation:

Step 1: Write equation

5x - 7(x + 1) = 9

Step 2: Solve for <em>x</em>

  1. Distribute -7: 5x - 7x - 7 = 9
  2. Combine like terms: -2x - 7 = 9
  3. Add 7 to both sides: -2x = 16
  4. Divide both sides by -2: x = -8

Step 3: Check

<em>Plug in x to verify it's a solution.</em>

5(-8) - 7(-8 + 1) = 9

-40 - 7(-7) = 9

-40 + 49 = 9

9 = 9

8 0
3 years ago
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Hey Carpender buys $54.38 worth of parts for a supplier if he pays for the parts with the heart of the bill how much change will
Tcecarenko [31]
A carpenter buys $54.38 worth of parts from a supplier. if he pays for the parts with a $100 dollar bill, he will receive 100 minus 54.38 = 45.62 in change
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5 0
3 years ago
Which of these rational numbers is the product of the other six? 2/99, 2/3, 5/7, 2 1/4, 2 1/3, 10/11, 18
Vesnalui [34]

Answer:

10/11

multiply to check on calculator

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3 years ago
What 3 digit number has tens digit that is 5 more than the ones digit and a hundreds digit that is 8 less than the tens digit?
Darina [25.2K]
194 is your answer. 
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8 0
3 years ago
Find the area of the region enclosed by the graphs of the functions
Vaselesa [24]

Answer:

\displaystyle A = \frac{8}{21}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Algebra I</u>

  • Terms/Coefficients
  • Functions
  • Function Notation
  • Graphing
  • Solving systems of equations

<u>Calculus</u>

Area - Integrals

Integration Rule [Reverse Power Rule]:                                                                 \displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C

Integration Rule [Fundamental Theorem of Calculus 1]:                                      \displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)

Integration Property [Addition/Subtraction]:                                                          \displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx

Area of a Region Formula:                                                                                     \displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx

Step-by-step explanation:

*Note:

<em>Remember that for the Area of a Region, it is top function minus bottom function.</em>

<u />

<u>Step 1: Define</u>

f(x) = x²

g(x) = x⁶

Bounded (Partitioned) by x-axis

<u>Step 2: Identify Bounds of Integration</u>

<em>Find where the functions intersect (x-values) to determine the bounds of integration.</em>

Simply graph the functions to see where the functions intersect (See Graph Attachment).

Interval: [-1, 1]

Lower bound: -1

Upper Bound: 1

<u>Step 3: Find Area of Region</u>

<em>Integration</em>

  1. Substitute in variables [Area of a Region Formula]:                                     \displaystyle A = \int\limits^1_{-1} {[x^2 - x^6]} \, dx
  2. [Area] Rewrite [Integration Property - Subtraction]:                                     \displaystyle A = \int\limits^1_{-1} {x^2} \, dx - \int\limits^1_{-1} {x^6} \, dx
  3. [Area] Integrate [Integration Rule - Reverse Power Rule]:                           \displaystyle A = \frac{x^3}{3} \bigg| \limit^1_{-1} - \frac{x^7}{7} \bigg| \limit^1_{-1}
  4. [Area] Evaluate [Integration Rule - FTC 1]:                                                    \displaystyle A = \frac{2}{3} - \frac{2}{7}
  5. [Area] Subtract:                                                                                               \displaystyle A = \frac{8}{21}

Topic: AP Calculus AB/BC (Calculus I/II)  

Unit: Area Under the Curve - Area of a Region (Integration)  

Book: College Calculus 10e

6 0
3 years ago
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