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lakkis [162]
3 years ago
6

There were 63 Apples.. how much could two people get equally?

Mathematics
2 answers:
ozzi3 years ago
8 0
63/2
31.5/1 or 31 1/2 or 31.5

Hope this helps :)
lara [203]3 years ago
3 0
31 1/2 apples 1/2= half
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Tony wants to buy a new flatscreen TV. At Best Buy, the TV costs $700, but Tony can use a 35% off coupon that he received in the
Lilit [14]
The cheaper option is Best Buy where the TV would close $455 compared to Micro Center which out be $480.
4 0
3 years ago
What two numbers add to make 36 with one of the numbers being exactly twice the other?
11111nata11111 [884]

Answer:

12 and 24

Step-by-step explanation:

2 numbers, x in this case, with one being twice the other, one of them will be 2x, equals 36. Your equation would look like this: 2x+x=36. Simplify it to get 3x=36, divide the 3 and you get 12. 12 will be your small number then multiply by 2 to get your large one, 24.

7 0
3 years ago
What is the greatest common factor of 3, 24, and 27
patriot [66]
GCF(3, 24, 27) = 3
Steps:

Prime factorization of the numbers:

3 = 3
24 = 2 × 2 × 2 × 3
27 = 3 × 3 × 3

GCF(3, 24, 27)
= 3
8 0
3 years ago
Read 2 more answers
Y=2x y=0.50x+18 solve by substitution
prohojiy [21]

Answer:

y = 18 + 0.50x

Step-by-step explanation:

I think that is the answer.

6 0
2 years ago
A particular state has elected both a governor and a senator. Let A be the event that a randomly selected voter has a favorable
Elodia [21]

Answer:

Step-by-step explanation:

Given that A be the event that a randomly selected voter has a favorable view of a certain party’s senatorial candidate, and let B be the corresponding event for that party’s gubernatorial candidate.

Suppose that

P(A′) = .44, P(B′) = .57, and P(A ⋃ B) = .68

From the above we can find out

P(A) = 1-0.44 = 0.56

P(B) = 1-0.57 = 0.43

P(AUB) = 0.68 =

0.56+0.43-P(A\bigcap B)\\P(A\bigcap B)=0.30

a) the probability that a randomly selected voter has a favorable view of both candidates=P(AB) = 0.30

b) the probability that a randomly selected voter has a favorable view of exactly one of these candidates

= P(A)-P(AB)+P(B)-P(AB)

=0.99-0.30-0.30\\=0.39

c) the probability that a randomly selected voter has an unfavorable view of at least one of these candidates

=P(A'UB') = P(AB)'

=1-0.30\\=0.70

3 0
3 years ago
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