Answer:
sin²x
Step-by-step explanation:
we have
(1 − cos x)(1 + cos x)=1-cos²x
Remember that
sin²x+cos²x=1 ------> i-cos²x=sin²x
therefore
(1 − cos x)(1 + cos x)=sin²x
Answer:
<h2>c. 2</h2>
Step-by-step explanation:
![4^\frac{1}{3}\cdot4^\frac{1}{6}\\\\\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=4^{\frac{1}{3}+\frac{1}{6}}=4^{\frac{1\cdot2}{3\cdot2}+\frac{1}{6}}=4^{\frac{2}{6}+\frac{1}{6}}=4^\frac{2+1}{6}=4^\frac{3}{6}=4^\frac{3:3}{6:3}=4^{\frac{1}{2}}\\\\\text{use}\ a^\frac{m}{n}=\sqrt[n]{a^m}\\\\=\sqrt[2]{4^1}=\sqrt4=2](https://tex.z-dn.net/?f=4%5E%5Cfrac%7B1%7D%7B3%7D%5Ccdot4%5E%5Cfrac%7B1%7D%7B6%7D%5C%5C%5C%5C%5Ctext%7Buse%7D%5C%20a%5En%5Ccdot%20a%5Em%3Da%5E%7Bn%2Bm%7D%5C%5C%5C%5C%3D4%5E%7B%5Cfrac%7B1%7D%7B3%7D%2B%5Cfrac%7B1%7D%7B6%7D%7D%3D4%5E%7B%5Cfrac%7B1%5Ccdot2%7D%7B3%5Ccdot2%7D%2B%5Cfrac%7B1%7D%7B6%7D%7D%3D4%5E%7B%5Cfrac%7B2%7D%7B6%7D%2B%5Cfrac%7B1%7D%7B6%7D%7D%3D4%5E%5Cfrac%7B2%2B1%7D%7B6%7D%3D4%5E%5Cfrac%7B3%7D%7B6%7D%3D4%5E%5Cfrac%7B3%3A3%7D%7B6%3A3%7D%3D4%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5C%5C%5C%5C%5Ctext%7Buse%7D%5C%20a%5E%5Cfrac%7Bm%7D%7Bn%7D%3D%5Csqrt%5Bn%5D%7Ba%5Em%7D%5C%5C%5C%5C%3D%5Csqrt%5B2%5D%7B4%5E1%7D%3D%5Csqrt4%3D2)
Answer: 1 : 20%
2 : 80%
3 : -90% (negative 90%), if no negatives are allowed, than it is a 90% decrease.
4 : $90
5: $31.50
Step-by-step explanation:
Combine all the "paid" amounts, then seperately combine all the "received" amounts. The ending balance would what is left over when you subtract the "paid" amounts from the "received" amounts:
Paid = (35+22+45) = ?
Received = (67 + 39) = ?
Ending Balance = Received - Paid = ?
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Answer:
