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melamori03 [73]
3 years ago
6

Simplify the expression: 7d +12-14d-3

Mathematics
1 answer:
Akimi4 [234]3 years ago
6 0
Group like terms
7d-14d+12-3
add them
-7d+9
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Determine the greatest common factor of the following: 4x^2y^2, 3xy^4, 2xy^2
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YOur greeatest common factor is 216. If you prime factor them it comes out to 216. Good luck.
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The cost of a ticket to the soccer game is 6$. There are y Number of people in a group that want to go to the game. Which of the
erastovalidia [21]
If each ticket cost six dollars and there is y amount of people it would be six for every person.
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3 years ago
What is the value of
Len [333]

n-2=10n+42\qquad\text{add 2 to both sides}\\\\n=10n+44\qquad\text{subtract 10n from both sides}\\\\-9n=44\qquad\text{divide both sides by (-9)}\\\\\boxed{n=-\dfrac{44}{9}}

8 0
3 years ago
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Mathematically verify the outlier(s) in the data set using the 1.5 rule.
statuscvo [17]

Given:

The data values are:

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

To find:

The outliers of the given data set.

Solution:

We have,

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

Divide the data set in two equal parts.

(7, 8, 11, 13, 14, 14), (14, 15, 16, 16, 18, 19)

Divide each parenthesis in two equal parts.

(7, 8, 11), (13, 14, 14), (14, 15, 16), (16, 18, 19)

Now,

Q_1=\dfrac{11+13}{2}

Q_1=\dfrac{24}{2}

Q_1=12

And

Q_3=\dfrac{16+16}{2}

Q_3=\dfrac{32}{2}

Q_3=16

The interquartile range is:

IQR=Q_3-Q_1

IQR=16-12

IQR=4

The data values lies outside the interval [Q_1-1.5IQR,Q_3+1.5IQR] are known as outliers.

[Q_1-1.5IQR,Q_3+1.5IQR]=[12-1.5(4),16+1.5(4)]

[Q_1-1.5IQR,Q_3+1.5IQR]=[12-6,16+6]

[Q_1-1.5IQR,Q_3+1.5IQR]=[6,22]

All the data values lie in the interval [6,22]. So, there are no outliers.

Hence, the correct option is 4.

3 0
3 years ago
Does a polygon usually have more sides or <br> more angles
xxTIMURxx [149]

I've seen this question on Brainly before, and I always shake my head.

Please think about this for a few seconds.  Maybe even make some
scribbles on a piece of paper.

-- A triangle has 3 sides and 3 angles.

-- A square, rectangle, rhombus or parallelogram has 4 sides and 4 angles.

-- Draw anything with 5 sides.  It doesn't have to be pretty, and they don't
all have to be the same length or anything special.  Just draw any shape
with 5 sides.  Count the angles, and you'll find that there are five of them.

By now you should be starting to get the creepy hunch that maybe a
polygon always has the SAME number of sides and angles.  I hope so. 
That's the correct creepy hunch. 

You can get all kinds of hunches, and even work most of them out,
just by using your thinker for a while.


5 0
3 years ago
Read 2 more answers
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