Answer:
Positive angles located in the fourth quadrant may be described as<u> 270≤Ф≤360
.</u>
The option is
4. 270≤Ф≤360
Step-by-step explanation:
When the terminal arm of an angle starts from the x-axis in the anticlockwise direction then the angles are always positive angles.
For Example.
Quadrant I - 0 to 90°
Quadrant II - 90° to 180°
Quadrant III - 180° to 270°
Quadrant IV - 270° to 360° ( 4. 270≤Ф≤360 )
Hence,Positive angles located in the fourth quadrant may be described as<u> 270≤Ф≤360
.</u>
When the terminal arm of an angle starts from the x-axis in the clockwise direction than the angles are negative angles.
Quadrant IV - 0° to -90°
Quadrant III - - 90° to -180°
Quadrant II - -180° to -270°
Quadrant I - -270° to -360°
Answer:
3, 50, 2
Step-by-step explanation:
By multiplying all terms by 5, we are trying to remove the fraction on the left hand side. On the right hand side of the equation, expand the bracket by multiplying 5 to each term in the bracket.
3(n +25)= 5(10) +5(
)
3(n +25)= 50 +2n
To find the value of n, expand the bracket on the left hand side:
3(n) +3(25)= 50 +2n
3n +75= 50 +2n
Bring all n terms to one side, constants to the other:
3n -2n= 50 -75
n= -25
It would be 0.35 because you need to multiply by 5 and then move the decimal 2 spaces to the right.
<span>X+2a = 16+aX-6a
8X - 16 = aX-2a
8(X-2) = a(X-2)
</span><span>(X-2)/<span>(X-2)</span> = a/8
1 = a/8
a= 8
</span>
Answer:
m=6
x=6
Can i please have brainliest? I never get brainliest. :(
