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77julia77 [94]
4 years ago
5

1. Show that l3+10l = l3l + l10l

Mathematics
1 answer:
Alborosie4 years ago
3 0
Those | | means that whatever the number inside is, will always be positive so it is equal
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Given ƒ(x) = x + 10 and g(x) = x2 + 5x - 1, find ƒ(3) + g(5).
SashulF [63]
If I’m not mistaken it should be 8x+25. :)
Hope this helps!
7 0
2 years ago
NEEP HELP ASAP!!!!!!!!!!!!!!!!!!!!!
stealth61 [152]

Step-by-step explanation:

sin 25 = 15 / xz

xz = 15/ sin 25

xz = 35.49

tan w = 35.49 / 22

w =58.15

8 0
2 years ago
1. Find the cost of levelling the ground in the form of a triangle having the sides 51 m, 37 m and 20 m at the rate of ₹ 3 per m
Flauer [41]

1. Find the cost of levelling the ground in the form of a triangle having the sides 51 m, 37 m and 20 m at the rate of ₹ 3 per m².

a = 51 m, b = 37 m, c = 20 m

semiperimeter:  p = (51+37+20):2 = 54 m

Area of triangle:

A=\sqrt{p(p-a)(p-b)(p-c)}\\\\A=\sqrt{54(54-51)(54-37)(54-20)}\\\\A=\sqrt{54\cdot3\cdot17\cdot34}\\\\A=\sqrt{9\cdot2\cdot3\cdot3\cdot17\cdot17\cdot2}\\\\A=3\cdot2\cdot3\cdot17\\\\A=306\,m^2

Rate:  ₹ 3 per m².

Cost:  ₹ 3•306 = ₹ 918

2. Find the area of the isosceles triangle whose perimeter is 11 cm and the base is 5 cm.

a = 5 cm

a+2b = 11 cm  ⇒  2b = 6 cm   ⇒  b = 3 cm

p = 11:2 = 5.5

A=\sqrt{5.5(5.5-3)^2(5.5-5)}\\\\ A=\sqrt{5.5\cdot(2.5)^2\cdot0.5}\\\\ A=\sqrt{11\cdot0.5\cdot(2.5)^2\cdot0.5}\\\\A=0.5\cdot2.5\cdot\sqrt{11}\\\\A=1.25\sqrt{11}\,cm^2\approx4.146\,cm^2

3. Find the area of the equilateral triangle whose each side is 8 cm.

a = b = c = 8 cm

p = (8•3):2 = 12 cm

A=\sqrt{12(12-8)^3}\\\\ A=\sqrt{12\cdot4^3}\\\\ A=\sqrt{3\cdot4\cdot4\cdot4^2}\\\\A=4\cdot4\cdot\sqrt{3}\\\\A=16\sqrt3\ cm^2\approx27.713\ cm^2

4. The perimeter of an isosceles triangle is 32 cm. The ratio of the equal side to its base is 3 : 2. Find the area of the triangle.

a = 2x

b = 3x

2x + 2•3x = 32 cm  ⇒ 8x = 32 cm   ⇒  x = 4 cm  ⇒ a = 8 cm, b = 12 cm

p = 32:2 = 16 cm

A=\sqrt{16(16-8)(16-12)^2}\\\\ A=\sqrt{16\cdot8\cdot4^2}\\\\ A=\sqrt{2\cdot8\cdot8\cdot4^2}\\\\ A=8\cdot4\cdot\sqrt2\\\\ A=32\sqrt2\ cm^2\approx45.2548\ cm^2

8 0
3 years ago
I’m a right triangle the length of the hypotenuse is 12and the length of one leg is 8 . What is the length of the other leg?
denis23 [38]

Answer:

other leg is 8.94

Step-by-step explanation:

Pythagorean Theorem  is a² + b² = c²

a and b are legs

c is the hypotenuse

8² + b² = 12²

64 + b² = 144

-64          -64

        b² = 80

        √b² = √80

         b ≈ 8.94

3 0
3 years ago
The length of a rectangle is 12 cm more than its width. Find the
just olya [345]

Dimensions of the rectangle (width and length) are 19 cm and 31 cm respectively.

Step-by-step explanation:

  • Step 1: Given that the perimeter = 100 cm, let width be x cm and then length = 12 + x.

Perimeter of a rectangle = 2(length + width)

100 = 2(x + 12 + x)

100 = 4x + 24

4x = 100 - 24 = 76

∴ x = 76/4 = 19 cm

∴ Length = 19 + 12 = 31 cm

5 0
4 years ago
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