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Elanso [62]
2 years ago
15

D=-0.5t + 7I REALLY NEED HELP ASAP I WILL MARK BRAINLIEST TYTY​

Mathematics
1 answer:
serg [7]2 years ago
6 0

Answer:

7.5t

Step-by-step explanation:

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the answer does be 7875810503.17

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A length of chain is to be constructed by placing 36 component links end to end. The length of a link produced by a production p
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d. 90 cm, 1.2 cm

Step-by-step explanation:

Given that:

The sample size n = 36

For the  length of the link:

The mean \overline x = 2.5

The standard deviation s = 0.2 cm

In a chosen 36 links, The mean and standard deviation for the length chain is as follows:

Mean = n\overline x

Mean = 36×2.5

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The Standard deviation = 0.2×√36

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5 0
3 years ago
A computer store buys a computer system at a cost of $457.80.The selling price was set at $763, but after a year the computer di
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3 years ago
find the width of radius r if the width w of the shaded region is 2cm and its area is 176cm^2, use 22/7 for pi (its a full circl
arsen [322]

The area of a shape is the amount of space it can occupy.

<em>The value of r is 13</em>

From the question (see attachment), we have:

\mathbf{A =176} --- area of the shaded region

\mathbf{w = 2} --- the width of the shaded region

The area of the complete circle would be:

\mathbf{A_1 =\pi (r + w)^2}

The area of the small circle is:

\mathbf{A_2 =\pi r^2}

So, the area of the shaded region is:

\mathbf{A = A_1 -  A_2}

Substitute known values

\mathbf{176 =\pi (r + w)^2 - \pi r^2 }

Substitute 2 for w

\mathbf{176 =\pi (r + 2)^2 - \pi r^2 }

Expand

\mathbf{176 =\pi (r^2 + 4r + 4) - \pi r^2 }

Open brackets

\mathbf{176 =\pi r^2 + 4\pi r + 4\pi - \pi r^2 }

Cancel out line terms

\mathbf{176 =4\pi r + 4\pi }

Divide through by 4

\mathbf{44 =\pi r + \pi }

Factor out pi

\mathbf{44 =\pi(r+ 1) }

Divide through by pi

\mathbf{r + 1= \frac{44}{ \pi} }

Substitute 22/7 for pi

\mathbf{r + 1= \frac{44}{ 22/7} }

Using a calculator, we have

\mathbf{r + 1= 14}

Solve for r

\mathbf{r= 14 -1}

\mathbf{r= 13}

Hence, the value of r is 13

Read more about areas of circles at:

brainly.com/question/23328170

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