Answer:
Option C is right.
Step-by-step explanation:
Given is a graph with two triangles marked on it.
Triangle ABC is in the I quadrant with vertices (2,2) (2,10) and (8,12)
Triange A'B'C' is in the III quadrant with vertices (-1,-1), (-1,-5) and (-4,-6)
On comparison we find corresponding side of AB is A'B'
Length of AB = 8 and Length of A'B' = 4.
Hence A'B'C' is obtained by dilating ABC by a scale factor of 1/2.
Now since moved to III quadrant from I quadrant we find that there is a rotation of triangle ABC about the origin. The degree of rotation is 180 degrees.
Hence A'B'C' is obtained by dilating ABC by a scale factor of 1/2 and then rotating it about the origin by 180 degrees
Discriminant D is given by:
D=b²-4ac
Implication of discriminant is as follows:
D<0 two zeros that are complex conjugate
D=0 one real zero of multiplicity 2
D>0 two distinct real zers
D= (+ve perfet square) two distinct rational zeros
From:
12x^2+10x+5=0
plugging in the equation we get:
10²-4×12×5
=100-240
=-140
thus
D<0
Answer is:
<span>A two irrational solutions </span>
Answer:
Solution given:
For rectangle
length [L]=BC=16in
breadth [b]=AB=4in
For traingle
length[l]=8in
breadth [b]=3in
total area =area of rectangle ABCD+2×area of triangle DEF
=L×b+2×1/2×[b×h]
=16×4+8×3=88in² is your answer
#7
20%•$300
$60
300-60
240
Hope this helps!!
The conversion factor between kilo and base unit which is grams in this question is 1000 so there is 1000 grams in 1 kilogram so first we need to convert kilograms to grams so we multiply by 1000 so 30kgx1000= 30000 grams so to find the number of crayons then we divide by 30 which is the mass of one crayon to find out how many we need so 30000/30= 1000 so you would need 1000 crayons
