Answer: A= 110 B=22.5 C=0
Step-by-step explanation:
Answer:
Can you please tell me what is the area of the given triangle?

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
Answer: 30
Step-by-step explanation:
3+4+3=10 400/10=40 so each has 40 so math has 120 120*25=3000 for physics is 4*40 so 160 160*20=3200 9800-3000-3200=3600 3*40=120 3600/120=30
Answer:
Step-by-step explanation:
<u><em>To Determine:</em></u>
Solve for x and find angle LMN.
<u><em>Fetching Information and Solution Steps:</em></u>
Considering the angle 
As MO bisects the angle
into two equal angle parts. These equal angles are:


As these angles are equal. i.e.












Hence, 
As
was cut into two equal parts
and 
So,
= 
= 
= 
=
∵ 
= 
Therefore, 
Keywords: angle bisector, congruent angles
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