Answer:
(8x²+7y²–z²+2yz+3xz–5xy) × ( 2x–3y)
= (16x³+14xy²–2z²x+4yzx+6x²z–10x²y –24yx²–21y³+3z²y–6y²z–9xzy+15xy²)
=( 16x³+29xy²–2z²x–5xyz+6x²z–34x²y–21y³+3z²y–6y²z)
I hope I helped you^_^
Associative property is when you move the grouping symbols: ( and )
So the answer is B.
Answer:
D
(4y-5)(3x-5)
Step-by-step explanation:
12xy -15x -20y +25
I will factor by grouping
12xy -15x -20y +25
Factor out 3x from the first group and -5 from the second group
3x(4y-5) -5(4y-5)
Now factor out (4y-5)
(4y-5)(3x-5)
This is impossible to answer without knowing what the sets A and B contain (and what ξ even refers to - universal set?).
However, we have
(A U B)' = A' ∩ B'
so that
(A ∩ B) U (A U B)' = (A ∩ B) U (A' ∩ B') = (A U A') ∩ (B U B')
If ξ is indeed the universal set, then both A U A' = ξ and B U B' = ξ, so we end up with ξ ∩ ξ = ξ.
Answer:
D) 35x³ - 16x² + 44x - 48
Step-by-step explanation:
(5x2 + 2x + 8)(7x – 6) = (5x2 + 2x + 8)* 7x + (5x2 + 2x + 8)*(– 6)
= (5x2*7x + 2x*7x + 8*7x) + (5x2*(-6) + 2x*(-6) + 8*(-6) )
=35x³ + 14x² + 56x - 30x² - 12x - 48
= 35x³ - 16x² + 44x - 48
