Try graphing using the x-intercept and y-intercept.
-15x - 5y = 45
Put in x = 0 to get -5y = 45, making y = -9. Point (0, -9) is on the line.
Put in y = 0 to get -15x = 45, making x = -3. Point (-3, 0) is on the line.
-2x + 6y = 6
Put in x = 0 to get 6y = 6, making y = 1. Point (0, 1) is on the line.
Put in y = 0 to get -2x = 6, making x = -3. Point (-3, 0) is on the line.
(We've actually stumbled on the solution since (-3, 0) is on both lines!)
Graph the two lines using the points found above.
The solution is x = -3, y = 0.
The equation in the form of the given expression is (0)² + (1)² = 1
<h3>Trigonometry identity</h3>
According to some of the trigonometry identity
sin 0 = 0
cos 0 1
Given the expression below
sin^2 0+cos^2 0=1
This can also be expressed as:
(sin0)² + (cos0)² = 1
Substitute
(0)² + (1)² = 1
Hence the equation in the form of the given expression is (0)² + (1)² = 1
Learn more on trig identity here: brainly.com/question/20094605
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What is the range for this data set?<br> 22, 7, 14, 13, 38, 12, 19, <br> 17, 49, 13, 9, 18, 36
Degger [83]
Answer:
from 7 to 49 or (7, 49)
Step-by-step explanation:
Range means the limit of the data set. Basically, the low part of the range is the lowest number in the set and the high part of range is the highest part.
so let's use the vertex form of a parabola, since we know what its vertex coordinates are, let's use those, and then expand from there, so from the back to the front.
Answer:
Step-by-step explanation:
Given a function f, whose derivatives are f' and f'', a value x is a critical point if f'(x) =0. A value x is a minimum of f if it is a critical point and f''(x) >0 and it is maximum if f''(x)<0. We will perfom the following steps:
1. Calculate the derivative f'.
2. Solve f'(x) =0.
3. Determine if the x value found in 2 is a minimum or a maximum using f''.
Recall the following properties of derivatives
where c is a constant.
where f,g are differentiable.
where c is a constant.
(chain rule)
Case 1: f(x) = 2+3x+3.
Using the properties from above, we have
1.
2. The equation f'(x)=0 where f'(x) = 3 has no solution.
3. Based on the previous result, f has no maximum nor minimum.
Case 2:
1.
2. We have the equation
which is equivalent to
Recall that the cosine function only takes values in the set [-1,1]. So, this equation has no solution.
3. Based on the previous result, f has no maximum nor minimum.