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GaryK [48]
2 years ago
6

What is the range for this data set? 22, 7, 14, 13, 38, 12, 19, 17, 49, 13, 9, 18, 36​

Mathematics
1 answer:
Degger [83]2 years ago
5 0

Answer:

from 7 to 49 or (7, 49)

Step-by-step explanation:

Range means the limit of the data set. Basically, the low part of the range is the lowest number in the set and the high part of range is the highest part.

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Select the following series as arithmetic, geometric, or neither. 1 + 2 + 3 + 4 + . . . + 10
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2 years ago
Help ASAP!!<br>Using the graphed function above, find the following
Alenkinab [10]

Answer:

Maximum: 1, Minimum: -3, Midline y = -1, Amplitude = 4, Period = \pi, Frequency \displaystyle =\frac{1}{\pi},  equation : f(x)=-4cos(2x)+1

Step-by-step explanation:

<u>Sinusoid Functions</u>

It refers to the oscillating functions like the sine or cosine which range from a minimum and maximum value periodically.

The graph shown can give us all the information we need to answer these questions:

Maximum: 1

Minimum: -3

The midline goes through the center value (mean) of the max and min values, i.e.

Equation of the midline:

\displaystyle y=\frac{1-3}{2}=-1

Amplitude is the difference between the maximum and minimum values

A=1-(-3)=4

The period is the time it takes to complete a cycle. We can see the minimum value is first reached at x=0 and next at x=\pi

Thus the period is

T=\pi

The frequency is the reciprocal of the period:

\displaystyle f=\frac{1}{T}=\frac{1}{\pi}

The angular frequency is

\displaystyle w=2\pi f=\frac{2\pi }{\pi}=2

The equation of the function is a negative cosine (since it starts at the minimum) or a shifted sine or cosine. We'll choose the negative cosine, knowing all the parameters:

f(x)=-4cos(2x)+1

5 0
3 years ago
How do I simplify this?
Fudgin [204]
This is the theory of algebra, to simply the expression we proceed as follows;
[sqrt(x-2)+5/sqrt(x-2)]/(x-2)
simplifying the numerator we get:
sqrt(x-2)+5/sqrt(x-2)
=[x-2+5]/sqrt(x-2)
=(x+3)/sqrt(x-2)
therefore our entire expression will be:
[(x+3)/sqrt(x-2)]/(x-2)
[(x+3)/(x-2)^(1/2)]*1/(x-2)
applying the law if indices we get
=(x+3)/(x-2)^(3/2)
7 0
3 years ago
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