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konstantin123 [22]

3 years ago

8

I need help as soon as possible

1 answer:

bixtya [17]3 years ago

7 0

I believe the correct answer is -2

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F(x) = x2+3x+2 x2+5x+4 Why is there no zero at x = –1?

dmitriy555 [2]

You could rewrite $F(x)$ as

$\dfrac{x^2+3x+2}{x^2+5x+4}=\dfrac{(x+1)(x+2)}{(x+1)(x+4)}$

and be tempted to cancel out the factors of $x+1$ . But this cancellation is only valid when $x\neq-1$ .

When $x=-1$ , you end up with the indeterminate form $\dfrac00$ , which is why $-1$ is not a zero.

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Which are vertical angles? Check all that apply. ∠EAB and ∠BAC ∠EAB and ∠CAD ∠CAD and ∠FAE ∠CAB and ∠DAE ∠DAC and ∠DAE

Anastaziya [24]

Answer:

<CAB and <DAE are vertical angles

<EAB and <CAD are vertical angles

Step-by-step explanation:

this is because they are formed by the prolongation of the sides of the other angles and are opposite to them on the other side of the vertex.

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dem82 [27]

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37.5 percent !!

Step-by-step explanation:

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Gelneren [198K]

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