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3 years ago

I need help as soon as possible

Mathematics

1 answer:

bixtya [17]3 years ago

7 0

I believe the correct answer is -2

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There were a total of 209 basketball games in the season the season played is for 19 months how many basketball games were playe

dangina [55]

Answer:

Step-by-step explanation:

divide 209 by 19 to get an equal number of games each month (for 19 months), you will get 11 games each month.

6 0

2 years ago

Read 2 more answers

each truck in the line weigh two tons more than the truck before it. the trucks weigh a total of 32 tons.how many pounds does a

mixer [17]

If there are 4 trucks then the first truck weighs x
then x+2tons
then x+4tons
then x+6tons = 32tons
so 4x+12=32
-12 -12
/4 /4
x=5
so plug it back in
truck 1= 5tons or 10,000lbs
truck 2= 7tons or 14,000lbs
truck 3= 9tons or 18,000lbs
<span>truck 4= 11tons or 22,000lbs</span>

6 0

3 years ago

Compare the rates to find which is the best value.

sattari [20]

Answer:

C6 greeting cards for $23.40

Step-by-step explanation:

A. 13.5/3=4.5

B. 38.25/9=4.25

C. 23.4/6=3.9

d. 32.8/8=4.1

5 0

2 years ago

In a population of similar households, suppose the weekly supermarket expense for a typical household is normally distributed wi

Rina8888 [55]

Answer:

P(Y ≥ 15) = 0.763

Step-by-step explanation:

Given that:

Mean =135

standard deviation = 12

sample size n = 50

sample mean $\overline x$ = 140

Suppose X is the random variable that follows a normal distribution which represents the weekly supermarket expenses

Then,

$X \sim N ( \mu \sigma)$

The probability that X is greater than 140 is :

P(X>140) = 1 - P(X ≤ 140)

$P(X>140) = 1 - P( \dfrac{X-\mu}{\sigma} \leq \dfrac{140-135}{12})$

$P(X>140) = 1 - P( \dfrac{X-\mu}{\sigma} \leq \dfrac{5}{12})$

$P(X>140) = 1 - P( Z\leq0.42)$

From z tables,

$P(X>140) = 1 - 0.6628$

$P(X>140) = 0.3372$

Similarly, let consider Y to be the variable that follows a binomial distribution of the no of household whose expense is greater than $140

Then;

$Y \sim Binomial (np)$

$Y \sim Binomial (50,0.3372)$

∴

P(Y ≥ 15) = 1- P(Y< 15)

P(Y ≥ 15) = 1 - ( P(Y=0) + P(Y=1) + P(Y=2) + ... + P(Y=14) )

$P(Y \geq 15) = 1 - \begin {pmatrix} ^{50}_0 \end {pmatrix} (0.3372)^0 (1-0,3372)^{50} + \begin {pmatrix} ^{50}_1 \end {pmatrix} (0.3372)^1 (1-0,3372)^{49} + \begin {pmatrix} ^{50}_2 \end {pmatrix} (0.3372)^2 (1-0,3372)^{48} +... + \begin {pmatrix} ^{50}_{50{ \end {pmatrix} (0.3372)^{50} (1-0,3372)^{0}$

P(Y ≥ 15) = 0.763

7 0

3 years ago

In a semiconductor company's quality control test, a machine found that 14 out of a sample of 234 computer chips were defective.

ivann1987 [24]

Answer:

281-282

Step-by-step explanation:

4 0

2 years ago