The equation of a line that passes through (x1,y1) and has a slope of m is
y-y1=m(x-x1)
find slope
slope between (x1,y1) and (x2,y2) is
(y2-y1)/(x2-x1)
given
(-3,2) and (2,1)
slope=(1-2)/(2-(-3))=(-1)/(2+5)=-1/5
pikc a point
if we pick (-3,2)
(x1,y1)
x1=-3
y1=2
y-2=-1/5(x-(-3))
y-2=-1/5(x+3)
that is D
-12x^6 - 60x^5-75x^4.......GCF = 3x^4
3x^4(-4x^2 - 20x - 25)
3x^4(-2x - 5)(2x + 5) <==
Answer:
9 is your answer for x.
Step-by-step explanation:
Note the equal sign, what you do to one side, you do to the other. Isolate the variable, x. Do the opposite of PEMDAS.
PEMDAS is the order of operations, & =
Parenthesis
Exponent (& Roots)
Multiplication
Division
Addition
Subtraction
First, subtract 13 & 8x from both sides:
2x (-8x) + 13 (-13) = 8x (-8x) - 41 (-13)
2x - 8x = -41 - 13
Simplify. Combine like terms:
-6x = -54
Isolate the variable, x. Divide -6 from both sides:
(-6x)/-6 = (-54)/-6
x = (-54)/(-6)
x = 9
x = 9 is your answer.
~
To find the slope of the line:
(y2-y1)/(x2-x1)
(14-5)/(4-1)=(9)/(3)=3
Only one of your 4 possible answers has 3 as a slope. However, plugging in each point into the y=mx+b equation, the y-intercept consistently comes out as 2..
y=mx+b
14=3(4)+b b=2
5=3(1)+b b=2
y=3x+2
If there is a consistent, positive slope (from your question, this does not seem to have a quadratic as an option), 3x+5 is not even a viable solution because x=1 when the y-value is 5 (and thus no other x value {0} could have a y-value of 5). It seems as though you have a typo on your hands. Hopefully this helps?
