1.Read the passage given below.

Write the following expression in radical form

zlopas [31]

Answer:

See below

Step-by-step explanation:

Write the following expression in radical form

(8x)¹/² = $\sqrt{8x}$

Write the following expression in exponential form.

$\sqrt{19}$ = 19¹/²

8 0

2 years ago

Can someone please help me with this question

kondor19780726 [428]

A.

To solve, you need to get the variable by itself.
Order of operations:
Square root both sides.
(x-5)= plus/minus root 3, as 3 is not a perfect square.
Now you need to add 5 to both sides to get it to disappear on the side with the x.

x=root3 +or - 5, which can be rearranged so that 5 is the first term.

8 0

2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=2x%2B7-1%3D2x%2B7" id="TexFormula1" title="2x+7-1=2x+7" alt="2x+7-1=2x+7" align="absmiddle" cl

Goshia [24]

Answer:

Step-by-step explanation:

$2x + 7 - 1 = 2x + 7$

$= > 2x - 1 = 2x + 7 - 7$

$= > 2x - 1 = 2x$

$= > - 1 = 2x - 2x$

$= > x = - 1$

7 0

2 years ago

A can of apple juice contains 175 calories per 2.5 servings at this rate how many calories are in 4 servings

user100 [1]

Uhmmm i lost the answer while doing this

8 0

2 years ago

Read 2 more answers

Which of the following graphs shows the solution set for the inequality below? 3|x + 1| < 9

Bas_tet [7]

Step-by-step explanation:

The absolute value function is a well known piecewise function (a function defined by multiple subfunctions) that is described mathematically as

$f(x) \ = \ |x| \ = \ \left\{\left\begin{array}{ccc}x, \ \text{if} \ x \ \geq \ 0 \\ \\ -x, \ \text{if} \ x \ < \ 0\end{array}\right\}$ .

This definition of the absolute function can be explained geometrically to be similar to the straight line $\textbf{\textit{y}} \ = \ \textbf{\textit{x}}$ , however, when the value of x is negative, the range of the function remains positive. In other words, the segment of the line $\textbf{\textit{y}} \ = \ \textbf{\textit{x}}$ where $\textbf{\textit{x}} \ < \ 0$ (shown as the orange dotted line), the segment of the line is reflected across the x-axis.

First, we simplify the expression.

$3\left|x \ + \ 1 \right| \ < \ 9 \\ \\ \\\-\hspace{0.2cm} \left|x \ + \ 1 \right| \ < \ 3$ .

We, now, can simply visualise the straight line, $y \ = \ x \ + \ 1$ , as a line having its y-intercept at the point $(0, \ 1)$ and its x-intercept at the point $(-1, \ 0)$ . Then, imagine that the segment of the line where $x \ < \ 0$ to be reflected along the x-axis, and you get the graph of the absolute function $y \ = \ \left|x \ + \ 1 \right|$ .

Consider the inequality

$\left|x \ + \ 1 \right| \ < \ 3$ ,

this statement can actually be conceptualise as the question

$``\text{For what \textbf{values of \textit{x}} will the absolute function \textbf{be less than 3}}"$ .

Algebraically, we can solve this inequality by breaking the function into two different subfunctions (according to the definition above).

Case 1 (when $x \ \geq \ 0$ )

$x \ + \ 1 \ < \ 3 \\ \\ \\ \-\hspace{0.9cm} x \ < \ 3 \ - \ 1 \\ \\ \\ \-\hspace{0.9cm} x \ < \ 2$

Case 2 (when $x \ < \ 0$ )

$-(x \ + \ 1) \ < \ 3 \\ \\ \\ \-\hspace{0.15cm} -x \ - \ 1 \ < \ 3 \\ \\ \\ \-\hspace{1cm} -x \ < \ 3 \ + \ 1 \\ \\ \\ \-\hspace{1cm} -x \ < \ 4 \\ \\ \\ \-\hspace{1.5cm} x \ > \ -4$

*remember to flip the inequality sign when multiplying or dividing by

negative numbers on both sides of the statement.

Therefore, the values of x that satisfy this inequality lie within the interval

$-4 \ < \ x \ < \ 2$ .

Similarly, on the real number line, the interval is shown below.

The use of open circles (as in the graph) indicates that the interval highlighted on the number line does not include its boundary value (-4 and 2) since the inequality is expressed as "less than", but not "less than or equal to". Contrastingly, close circles (circles that are coloured) show the inclusivity of the boundary values of the inequality.

3 0

1 year ago