Answer:
Step-by-step explanation:
For this case we have the following distributions given:
The expected value for x is
And the variance
The expected value for x is
And the variance
We define a new random variable:
We need to find the expectd value and the variance for W.
For the expected value we have this:
And if we replace the parameters we got:
Now foe tha variance of W we know that X and Y are indpenendet variable so then
For this case we can use the property that is a is a constant and X a random variable then , and we got this:
And if we replace we got:
Answer:
4x+8
Step-by-step explanation:
Answer:
Distance=520cm
Step-by-step explanation:
The solution is in the image
Answer:
A
Step-by-step explanation:
let y = f(x) and rearrange making x the subject, that is
y = ( multiply both sides by x³ )
x³y = 19 ( divide both sides by y )
x³ = ( take the cube root of both sides )
x =
Change y back into terms of x, then
(x) = = → A
The question is asking how many combinations of two people can be made from a group of ten people.
Using the formula C(10,2) = 10!/(2! x (10 - 2)! = 10!/(2! x 8!) = 45 handshakes.
A simple way to prove this is each person shakes the hand of 9 other people
10 x 9 = 90 but this counts every handshake from the view of both people involved.
The actual number of handshakes is therefore 90 / 2 = 45