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Shalnov [3]
3 years ago
7

Three times the sum of a number and four is twenty-one. Find the number. The number is ___

Mathematics
2 answers:
Nady [450]3 years ago
6 0

Answer:

The answer to your question is: x = 3

Step-by-step explanation:

                                            3(x + 4) = 21

                                              x  + 4 = 21/3

                                             x + 4 = 7

                                            x = 7 - 4

                                            x = 3

cupoosta [38]3 years ago
5 0

Answer:

n = 9/3 = 3

Step-by-step explanation:

Translating these words into symbolic statements:

3(n + 4) = 21.

Perform the indicated multiplication, obtaining:

3n + 12 = 21

Combine the constant terms:  3n = 9

Finally, solve this for n: n = 9/3 = 3

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Ksenya-84 [330]

a = 3, b= - 4 and c = - 4

expand the left side using FOIL

(2x + 1)(ax + b) = 2ax² + 2bx + ax + b = 2ax² + x(2b + a) + b

compare the coefficients of expressions on left and right sides.

compare 2ax² + x(2b +a) + b with 6x² - 5x + c

coefficients of x² terms → 2a = 6 ⇒ a = 3

coefficients of x terms → 2b + a = - 5 → 2b + 3 = - 5 → 2b = - 8 ⇒ b = - 4

constant terms c = b = - 4


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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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