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Liula [17]
3 years ago
7

A chef needs to make 8 servings of fruit salad. He has 2 1/2 pounds of fruit salad. How much fruit salad will be in each serving

?
Mathematics
1 answer:
iVinArrow [24]3 years ago
5 0
2.5lb/8 servings
2.5/8 = 0.3125lb
There will be 0.3125lb of fruit salad in each serving
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Use the complex conjugate to find the absolute value of 8+12i
Anastaziya [24]

Answer:

A. 12

Step-by-step explanation:

i= use complicated conjugate to search out definite quantity of 8 + 12i

i = 12i

i= twelve × ei 90°

i = twelve × (cos 90° + i sin 90°)

r = |i| = twelve


6 0
3 years ago
6) 6n+ 3 = 3(-7n + 1)<br> what did you guys get for the answer?
Allushta [10]

Answer:

n=0

Step-by-step explanation:

Clear parenthesis w/ distribution:

3(-7n+1)=-21n+3

Move everything over to one side:

6n+3=-21n+3

6n=21n                                                   Subtract the 3 on the right.

-15n=0                                                                      Subtract the 21.

n=0                                                                              Divide the -15.

5 0
3 years ago
Read 2 more answers
A random sample of 10 parking meters in a beach community showed the following incomes for a day. Assume the incomes are normall
Vlad1618 [11]

Answer: (2.54,6.86)

Step-by-step explanation:

Given : A random sample of 10 parking meters in a beach community showed the following incomes for a day.

We assume the incomes are normally distributed.

Mean income : \mu=\dfrac{\sum^{10}_{i=1}x_i}{n}=\dfrac{47}{10}=4.7

Standard deviation : \sigma=\sqrt{\dfrac{\sum^{10}_{i=1}{(x_i-\mu)^2}}{n}}

=\sqrt{\dfrac{(1.1)^2+(0.2)^2+(1.9)^2+(1.6)^2+(2.1)^2+(0.5)^2+(2.05)^2+(0.45)^2+(3.3)^2+(1.7)^2}{10}}

=\dfrac{30.265}{10}=3.0265

The confidence interval for the population mean (for sample size <30) is given by :-

\mu\ \pm t_{n-1, \alpha/2}\times\dfrac{\sigma}{\sqrt{n}}

Given significance level : \alpha=1-0.95=0.05

Critical value : t_{n-1,\alpha/2}=t_{9,0.025}=2.262

We assume that the population is normally distributed.

Now, the 95% confidence interval for the true mean will be :-

4.7\ \pm\ 2.262\times\dfrac{3.0265}{\sqrt{10}} \\\\\approx4.7\pm2.16=(4.7-2.16\ ,\ 4.7+2.16)=(2.54,\ 6.86)

Hence, 95% confidence interval for the true mean= (2.54,6.86)

7 0
3 years ago
What is the slope between (-4,0) and (0,2)
zaharov [31]
The slope is y=1/2x + 2 or y= 0.5x+2
3 0
3 years ago
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What is an equation for the scenario the entrance fee to an amusement park is $9 plus $1.50 for each ride
MAVERICK [17]
E+r=
(e=9)
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or 9+1.50=
I think
3 0
3 years ago
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