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Evgesh-ka [11]
3 years ago
15

57/100 whats the part whats the whole

Mathematics
2 answers:
slavikrds [6]3 years ago
7 0

Answer:

The part is 57 and the whole is 100.

You could also put it as the part and the whole where the top number in the fraction, or the numerator, is the part because it is a part of 100. Meanwhile, the denominator is going to be the whole. Hope your having a great day!

Explanation:

57/100

<em>57 = part   100 = whole</em>

Ostrovityanka [42]3 years ago
6 0
Hey, so in a fraction, the whole is always going to be the 2nd or bottom part of it. Why? Well if you were to read it out loud, you may as well say it as 57 out of 100, meaning that 57 is the part.
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Answer:

m = -2

Step-by-step explanation:

<em>Distribute first.</em>

24 = -6(m+1) + 18

24 = -6m - 6 + 18

<em>Then you combine like terms.</em>

24= -6m + 12

<em>Then you still combine like terms. You subtract 12 from each side.</em>

24 = -6m + 12

-12            - 12

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<em>Then divide by -6 to isolate the variable.</em>

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3 years ago
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A variety of stores offer loyalty programs. Participating shoppers swipe a bar-coded tag at the register when checking out and r
dsp73

Answer:

t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236    

Now we can find the degrees of freedom:

df=n-1=80-1=79  

Now we can calculate the p value with the alternative hypothesis using the following probability:

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Using a significance level of 0.01 or 1% we have enough evidence to FAIL to reject the null hypothesis and we can conclude that shoppers participating in the loyalty program NOT spent more on average than typical shopper at this significance level assumed

Step-by-step explanation:

Information given

\bar X=130 represent the sample mean

s=40 represent the sample standard deviation

n=80 sample size  

\mu_o =120 represent the value to verify

t would represent the statistic  

p_v represent the p value

System of hypothesis

We want to verify if  shoppers participating in the loyalty program spent more on average than typical shoppers (120) , the system of hypothesis would be:  

Null hypothesis:\mu \leq 120  

Alternative hypothesis:\mu > 120  

The statistic for this case is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info given we got:

t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236    

Now we can find the degrees of freedom:

df=n-1=80-1=79  

Now we can calculate the p value with the alternative hypothesis using the following probability:

p_v =P(t_{(79)}>2.236)=0.0141  

Using a significance level of 0.01 or 1% we have enough evidence to FAIL to reject the null hypothesis and we can conclude that shoppers participating in the loyalty program NOT spent more on average than typical shopper at this significance level assumed

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