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3 years ago

57/100 whats the part whats the whole

Mathematics

2 answers:

slavikrds [6]3 years ago

7 0

Answer:

The part is 57 and the whole is 100.

You could also put it as the part and the whole where the top number in the fraction, or the numerator, is the part because it is a part of 100. Meanwhile, the denominator is going to be the whole. Hope your having a great day!

Explanation:

57/100

<em>57 = part 100 = whole</em>

Ostrovityanka [42]3 years ago

6 0

Hey, so in a fraction, the whole is always going to be the 2nd or bottom part of it. Why? Well if you were to read it out loud, you may as well say it as 57 out of 100, meaning that 57 is the part.

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Sever21 [200]

Answer:

Step-by-step explanation:

With those problems if you are not given a picture is good we draw one.

Because an angle bisector forms 2 congruent angles and because is given that < XVY ≅ < YVW then

m < XVY = m < YVW

2x+7 = x+15 , subtract x and 7 from both sides to isolate the like terms

2x-x = 15-7, combine like terms

x = 8

From the picture and the given we see that

m < XVW = m < XVY + m < YVW

m < XVW = 2x+7 + x+15 , combine like terms

m < XVW = 3x + 22, substitute x for 8

m < XVW = 3*8 + 22

m < XVW = 46

Check our work:

m < XVY = 2x+7 = 2*8 +7 = 16 +7 = 23

m < YVW = x+15 = 8 +15 = 23

m < XVW = m < XVY + m < YVW = 23+23 =46

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2 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

What is the length of the side a ?<br><br> A=

vodka [1.7K]

Answer:

$a = 5$

Step-by-step explanation:

Notice that $\triangle CDB$ is a right triangle where its hypotenuse is $\overline{CB}$ . We can also see that $a = CB$ . For this we must use the Pythagorean Theorem.

Recall:

The Pythagorean Theorem states that if you have a right triangle, the principal square root of the sum of the squares of each leg is the length the hypotenuse.

We can see that $CD = 3$ and $DB = 4$

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3 years ago

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Brrunno [24]

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4 years ago

Write the equation of a line passing through (6,-2) and perpendicular to -2x + 3y= -6

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Perpendicular lines refers to a pair of straight lines that intercept each other. The slopes of this lines are opposite reciprocal, meaning that it's multiplication is -1.
On this case they give you the equation of a line and a point, and is asked to find the equation of a line that is perpendicular to the given one, and that passes through this point.

-2x+3y=-6 Add 2x in both sides
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The slope of the given line is 2/3, which means that the slope of a line perpendicular to this one, needs to be -3/2. Now you need to find the value of b or the y-intercept by substituting the given point into the formula y=mx+b, where letter m represents the slope.

y=mx+b Substitute the given point and the previous slope found
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The equation that represents the line perpendicular to -2x+3y=-6 and that passes through the point (6,-2), is y=-3/2x+7.

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3 years ago