Supplementary. this means they add up to 180°
The bearing of the plane is approximately 178.037°. 
<h3>Procedure - Determination of the bearing of the plane</h3><h3 />
Let suppose that <em>bearing</em> angles are in the following <em>standard</em> position, whose vector formula is:
(1)
Where:
- Magnitude of the vector, in miles per hour.
- Direction of the vector, in degrees.
That is, the line of reference is the
semiaxis.
The <em>resulting</em> vector (
), in miles per hour, is the sum of airspeed of the airplane (
), in miles per hour, and the speed of the wind (
), in miles per hour, that is:
(2)
If we know that
,
,
and
, then the resulting vector is:

![\vec v = (7.986, -232.981) \,\left[\frac{mi}{h} \right]](https://tex.z-dn.net/?f=%5Cvec%20v%20%3D%20%287.986%2C%20-232.981%29%20%5C%2C%5Cleft%5B%5Cfrac%7Bmi%7D%7Bh%7D%20%5Cright%5D)
Now we determine the bearing of the plane (
), in degrees, by the following <em>trigonometric</em> expression:
(3)


The bearing of the plane is approximately 178.037°. 
To learn more on bearing, we kindly invite to check this verified question: brainly.com/question/10649078
Answer:
The first one
Step-by-step explanation:
Answer:
170
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error is of:

Assume:

90% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
What is the smallest sample size required to obtain the desired margin of error?
This is n for which M = 0.03. So






Rounding up, 170.