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kramer
3 years ago
10

Complete the table. table Distances:

Mathematics
2 answers:
castortr0y [4]3 years ago
7 0

Answer:

a = 4

f = 36

b = 4

d = 16

g = 64

Step-by-step explanation:

Sever21 [200]3 years ago
5 0

Answer:79

Step-by-step explanation:78: I love the noise

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Thepotemich [5.8K]
Supplementary. this means they add up to 180°
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3 years ago
PLEASE HELP! 50 Points!
gulaghasi [49]

The bearing of the plane is approximately 178.037°. \blacksquare

<h3>Procedure - Determination of the bearing of the plane</h3><h3 />

Let suppose that <em>bearing</em> angles are in the following <em>standard</em> position, whose vector formula is:

\vec r = r\cdot (\sin \theta, \cos \theta) (1)

Where:

  • r - Magnitude of the vector, in miles per hour.
  • \theta - Direction of the vector, in degrees.

That is, the line of reference is the +y semiaxis.

The <em>resulting</em> vector (\vec v), in miles per hour, is the sum of airspeed of the airplane (\vec v_{A}), in miles per hour, and the speed of the wind (\vec v_{W}), in miles per hour, that is:

\vec v = \vec v_{A} + \vec v_{W} (2)

If we know that v_{A} = 239\,\frac{mi}{h}, \theta_{A} = 180^{\circ}, v_{W} = 10\,\frac{m}{s} and \theta_{W} = 53^{\circ}, then the resulting vector is:

\vec v = 239 \cdot (\sin 180^{\circ}, \cos 180^{\circ}) + 10\cdot (\sin 53^{\circ}, \cos 53^{\circ})

\vec v = (7.986, -232.981) \,\left[\frac{mi}{h} \right]

Now we determine the bearing of the plane (\theta), in degrees, by the following <em>trigonometric</em> expression:

\theta = \tan^{-1}\left(\frac{v_{x}}{v_{y}} \right) (3)

\theta = \tan^{-1}\left(-\frac{7.986}{232.981} \right)

\theta \approx 178.037^{\circ}

The bearing of the plane is approximately 178.037°. \blacksquare

To learn more on bearing, we kindly invite to check this verified question: brainly.com/question/10649078

5 0
3 years ago
In ΔIJK, k = 7.2 cm, ∠J=55° and ∠K=67°. Find the length of i, to the nearest 10th of a centimeter.
almond37 [142]

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6.6

Step-by-step explanation:

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Which image shows the correct position -2 1/2on the number line ​
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Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Jonah wants to construct a confidence interval using 90% confidence to estimate what proportion of silicon wafers at his factory
Nimfa-mama [501]

Answer:

170

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

Assume:

\pi = 0.06

90% confidence level

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

What is the smallest sample size required to obtain the desired margin of error?

This is n for which M = 0.03. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.06*0.94}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.06*0.94}

\sqrt{n} = \frac{1.645\sqrt{0.06*0.94}}{0.03}

(\sqrt{n})^2 = (\frac{1.645\sqrt{0.06*0.94}}{0.03})^2

n = 169.6

Rounding up, 170.

4 0
3 years ago
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