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VladimirAG [237]
3 years ago
9

John ran the​ 100-m dash with a time of 9.96 sec. If this pace could be maintained for an entire 26-mi ​marathon, what would his

time​ be?
Mathematics
1 answer:
soldi70 [24.7K]3 years ago
3 0
We know that 
1 mile----------------> 1609.34 meters
26 miles---------------> X
X=26*1609.34=41842.84 m

I apply a rule of three to know the time

if 100 m---------------9.96 sec
41842.84 m----------> x
x=41842.84*9.96/100=4167.5468 sec

to get minutes I divide it by 60---------> 4167.5468/60=69.459113 minutes

to get hours I divide it by 60----------> 69.459113/60=1.1576518 hours

1.1576518= 1 hour 9 minutes 27.55 sec

the answer is 1 hour 9 minutes 27.55 sec------->(4167.5468 sec)

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1 .i think it is d

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Can someone help with numbers 1 and 2 for both of them tell me the answer and how you get it please I need the two of them do no
algol [13]

Answer:

look it up

Step-by-step explanation:

L.O.O.K   I.T      U.P.

5 0
3 years ago
How do you do this question?
Alex Ar [27]

Step-by-step explanation:

(a) dP/dt = kP (1 − P/L)

L is the carrying capacity (20 billion = 20,000 million).

Since P₀ is small compared to L, we can approximate the initial rate as:

(dP/dt)₀ ≈ kP₀

Using the maximum birth rate and death rate, the initial growth rate is 40 mil/year − 20 mil/year = 20 mil/year.

20 = k (6,100)

k = 1/305

dP/dt = 1/305 P (1 − (P/20,000))

(b) P(t) = 20,000 / (1 + Ce^(-t/305))

6,100 = 20,000 / (1 + C)

C = 2.279

P(t) = 20,000 / (1 + 2.279e^(-t/305))

P(10) = 20,000 / (1 + 2.279e^(-10/305))

P(10) = 6240 million

P(10) = 6.24 billion

This is less than the actual population of 6.9 billion.

(c) P(100) = 20,000 / (1 + 2.279e^(-100/305))

P(100) = 7570 million = 7.57 billion

P(600) = 20,000 / (1 + 2.279e^(-600/305))

P(600) = 15170 million = 15.17 billion

7 0
2 years ago
Olivia is adding the numbers 25, 35, and 9. She wants to make a ten to add. Which ones digits does Olivia add first?
Nimfa-mama [501]

Answer:

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Step-by-step explanation:

6 0
3 years ago
Jose asks his friends to guess the higher of two grades he received on his math tests. He gives them two hints. The difference o
AlekseyPX

Answer : 96

x – y = 16 --------> equation 1

\frac{1}{8} x +\frac{1}{2} y = 52

x is the higher grade and y is the lower grade

We solve the first equation for y

x - y = 16

-y = 16 -x ( divide each term by -1)

y = -16 + x

Now substitute y in second equation

\frac{1}{8} x +\frac{1}{2} ( -16 + x ) = 52

\frac{1}{8} x - 8 +   \frac{1}{2} x = 52

\frac{1}{8} x  +   \frac{1}{2} x - 8 = 52

Take common denominator to combine fractions

\frac{1}{8} x  +   \frac{4}{8} x  -8 = 52

\frac{5}{8} x - 8  = 52

Add 8 on both sides

\frac{5}{8} x   = 60

Multiply both sides by \frac{8}{5}

x = 96

We know x is the higher grade

96 is the higher grade of Jose’s two tests.

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3 years ago
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