The answer to your question is: x=10. y=2
Answer:
4th one
2x-10<12-6x
Step-by-step explanation:
2(x-5)=2x-10
3(4-2x)=12-6x
So: 2(x-5)<3(4-2x) is
2x-10<12-6x
Números que suman 6:
3 + 2 + 1 = 6=> 3^2 + 2^2 + 1^2 = 9 + 4 + 1 = 14
4 + 3 - 1 = 6 => 4^2 + 3^2 + (-1)^2 = 16 + 9 + 1 = 26 => do not use negative numbers, because that will increase the other numbers.
5 + 1 + 0 = 6 => 5^2 + 1 + 0 = 25 + 1 + 0 = 26
4 + 2 + 0 = 4^2 + 2^2 + 0 = 16 + 4 = 20
When you use zero the you increase the sum of the squares.
Then the three numbers that yields the minimum sum of the squares is 1, 2 and 3.
Answer: A.
explanation: multiply 2 x 2= 4 then 4 x 2= 8 then 8 x 2= 16 then 16 x 2= 32 so basically your just multiplying every number by the same exact number which is 2
