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larisa86 [58]
3 years ago
9

Factor x 4 y 2 + x 3 y 3. a. x3y2(x + 1) b. x2y2(x + y) c. x3y2(x + y)

Mathematics
1 answer:
mylen [45]3 years ago
7 0

x^4 y^2 +x^3 y^3

GCF = x^3y^2

We factor out the GCF

So

x^3y^2 (x+y)

Option C is correct

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I need to verify identity functions for a one to one function.
Eddi Din [679]

We have the function

f(x)=(x+6)^3

1. For f^-1:

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Switch x and y to get:

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\begin{gathered} x^{\frac{1}{3}}=y+6 \\ x^{\frac{1}{3}}-6=y+6-6 \\ x^{\frac{1}{3}}-6=y \end{gathered}

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Answer blank 1:

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And solve

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answer blank 2

x^{\frac{1}{3}}-6

answer blank 3

x^{\frac{1}{3}}-6

answer blank 4

x^{\frac{1}{3}}

3. For f^-1 o f:

(f^{-1}\circ f)(x)=f^{-1}(f(x))

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answer blank 5

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answer blank 6

(x+6)^3

answer blank 7

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