Well, a linear function is proportional, a straight line (on a graph). And the numbers must not have the same answer. For instance, if the X input is 5, and the Y output is 7. And then another X input is 5, and the Y output is 8, that's non-linear.
So, the Answer would be the third graph. This is because the X values are steadily increasing, and so are the Y values.
For the X and Y values, for each time X increases by 1, Y increases by -8. This is, linear because both sides are constantly and evenly increasing.
Answer:
and ![M(T)=1.1(7(8+22^{10})^{3})=1.44\time10^{41}](https://tex.z-dn.net/?f=M%28T%29%3D1.1%287%288%2B22%5E%7B10%7D%29%5E%7B3%7D%29%3D1.44%5Ctime10%5E%7B41%7D)
Step-by-step explanation:
We have the next set of functions:
![L(T)=8+T^{10}](https://tex.z-dn.net/?f=L%28T%29%3D8%2BT%5E%7B10%7D)
![V(L)=7L^{3}](https://tex.z-dn.net/?f=V%28L%29%3D7L%5E%7B3%7D)
![M(V)=1.1V](https://tex.z-dn.net/?f=M%28V%29%3D1.1V)
We want to know M(T) then:
but we know that
:
and we know that ![L(T)=8+T^{10}](https://tex.z-dn.net/?f=L%28T%29%3D8%2BT%5E%7B10%7D)
![M(T)=1.1(7(8+T^{10})^{3})](https://tex.z-dn.net/?f=M%28T%29%3D1.1%287%288%2BT%5E%7B10%7D%29%5E%7B3%7D%29)
Finally using the value of 22º we have
![M(T)=1.1(7(8+22^{10})^{3})=1.44\time10^{41}](https://tex.z-dn.net/?f=M%28T%29%3D1.1%287%288%2B22%5E%7B10%7D%29%5E%7B3%7D%29%3D1.44%5Ctime10%5E%7B41%7D)
Answer:
no its not right
the line doesn't pass by (2,0) it passes by (2,1)
P = A(1+r)^x
where P is the population at time x
A is the initial population and r is the growth/decay rate. Growth will be +positive r number added to the 1. Where as decay subtracts r. So any answers that are > than 1 which is answers A and B.
Answer:
Step-by-step explanation:
Given
![\angle K = 90^o](https://tex.z-dn.net/?f=%5Cangle%20K%20%3D%2090%5Eo)
![KJ = 65](https://tex.z-dn.net/?f=KJ%20%3D%2065)
![IK = 72](https://tex.z-dn.net/?f=IK%20%3D%2072)
![JI = 97](https://tex.z-dn.net/?f=JI%20%3D%2097)
Required
![\cos(J)](https://tex.z-dn.net/?f=%5Ccos%28J%29)
The question is illustrated with the attached image.
From the image, we have:
![\cos(J) = \frac{KJ}{JI}](https://tex.z-dn.net/?f=%5Ccos%28J%29%20%3D%20%5Cfrac%7BKJ%7D%7BJI%7D)
This gives:
![\cos(J) = \frac{65}{97}](https://tex.z-dn.net/?f=%5Ccos%28J%29%20%3D%20%5Cfrac%7B65%7D%7B97%7D)
![\cos(J) = 0.67010309278](https://tex.z-dn.net/?f=%5Ccos%28J%29%20%3D%200.67010309278)
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