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svet-max [94.6K]
3 years ago
7

Jeanine Baker makes floral arrangements. She has 11 different cut flowers and plans to use 7 of them. How many different selecti

ons of the 7 flowers are​ possible?
Mathematics
1 answer:
Alex Ar [27]3 years ago
6 0

Answer:

<h2>330 different possible selections are there.</h2>

Step-by-step explanation:

There is a total of 11 cut flowers.

Jeanine Baker has to choose 7 flowers among the 11 flowers.

The formula for choosing r numbers from n numbers is defined by ^{n}C_{r} = \frac{n!}{r!\times(n - r)!}, n > r.

From 11 flowers 7 flowers can be chosen in ^{11} C {7} = \frac{11!}{7!\times4!} = \frac{8\times9\times10\times11}{2\times3\times4}. = 330 ways.

There are 330 possible ways to choose 7 flowers from 11 flowers.

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The concentration of carbon monoxide (CO) in a gas sample is measured by a spectrophotometer and found to be 85 ppm. Through lon
alukav5142 [94]

Answer:

The confidence interval is (85 - \frac{14.81}{\sqrt{n}},85 + \frac{14.81}{\sqrt{n}}), in which n is the size of the sample.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

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Now, find the margin of error M as such

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In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.645\frac{9}{\sqrt{n}} = \frac{14.81}{\sqrt{n}}

The lower end of the interval is the sample mean subtracted by M. So it is 85 - \frac{14.81}{\sqrt{n}}

The upper end of the interval is the sample mean added to M. So it is 85 + \frac{14.81}{\sqrt{n}}

The confidence interval is (85 - \frac{14.81}{\sqrt{n}},85 + \frac{14.81}{\sqrt{n}}), in which n is the size of the sample.

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