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2 years ago

Which transformations must be applied to object A to place it in the position of object B?

Mathematics

1 answer:

NeX [460]2 years ago

6 0

In order for object A to be placed in the position of object B, there needs to be a rotation and translation.

<h3>How would object A get to object B?</h3>

The first step would be to rotate object A to the left to give it the same orientation as object B.

Then, translate object A to the coordinates of object B. This would lead to object A fitting into object B.

Find out more on translation at brainly.com/question/1046778

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186 boxes. One hundred

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3 years ago

How do you show 28 X 20 on a visual model (pls show with dots) (ASAP)

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3 years ago

The length of the hypotenuse of the right triangle is 25 cm, the length of one of the legs is 10 cm. What is the length of the s

sergejj [24]

Answer:

$\large\boxed{AD=21\ and\ CD=2\sqrt{21}}$

Step-by-step explanation:

Look at the picture.

Use the Pythagorean theorem for calculate the length of CA:

$CA^2+CB^2=AB^2$

We have

$CA=x,\ CB=10,\ AB=25$

Substitute:

$x^2+10^2=25^2$

$x^2+100=625$ subtract 100 from both sides

$x^2=525\to x=\sqrt{525}\\\\x=\sqrt{25\cdot21}\\\\x=\sqrt{25}\cdot\sqrt{21}\\\\x=5\sqrt{21}\ cm$

ΔADC and ΔACB are similar. Therefore the corresponding sides are in proportion:

$\dfrac{AD}{AC}=\dfrac{AC}{AB}$

We have:

$AD=y,\ AC=5\sqrt{21},\ AB=25$

Substitute:

$\dfrac{y}{5\sqrt{21}}=\dfrac{5\sqrt{21}}{25}$

$\dfrac{y}{5\sqrt{21}}=\dfrac{\sqrt{21}}{5}$ cross multiply

$5y=5(\sqrt{21})^2$ divide both sides by 5

$y=21\ cm$

If you mean the length of segment CD, then use the proportion:

$\dfrac{CD}{AD}=\dfrac{CB}{CA}$

Substitute:

$\dfrac{CD}{21}=\dfrac{10}{5\sqrt{21}}\\\\\dfrac{CD}{21}=\dfrac{2}{\sqrt{21}}\qquad\text{cross multiply}\\\\CD\sqrt{21}=42\qquad\text{multiply both sides by}\ \sqrt{21}\\\\21CD=42\sqrt{21}\qquad\text{divide both sides by 21}\\\\CD=2\sqrt{21}\ cm$

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3 years ago

This chart shows a bamboo plants growth over 10hours. The plant grew at a constant speed what is the rate of speed for this bamb

blagie [28]

Answer:

???

Step-by-step explanation:

???

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3 years ago

The sum of two consecutive intergers is 139. Find the intergers

Elanso [62]

Let the Integer be x then its consecutive number will be x+1,

So, x+x+1=139,

2*x=138

x=69

The integers are 69,70

4 0

3 years ago