All categories

3 years ago

A 2,400 deposit for 8 years compounded at an annual interest rate of 4.5%

Mathematics

2 answers:

Alex3 years ago

8 0

IF WE HAVE TO FIND INTEREST THEN THE ANS IS GIVEN IN ATTACHED PICTURE.

HOPE THIS WILL HELP U...

Tomtit [17]3 years ago

3 0

Answer:

2400*8*.045= 864+2400=3264

Step-by-step explanation:

You might be interested in

for a walk-a-thon a sponsor committed to give to give you a flat fee of $5 plus $2 for every Mile you walk write an expression f

oksian1 [2.3K]

You will get 57.44’$

3 0

3 years ago

Right triangle similarity. what is the value of a?

kramer

Answer:

I'd say that a is 6 2/3 units long

Step-by-step explanation:

4 0

2 years ago

In a study of the accuracy of fast food drive-through orders, one restaurant had 36 orders that were not accurate among 324 ord

tia_tia [17]

Answer:

We do not have sufficient evidence to reject the claim that ,the rate of inaccurate orders is equal to 10%.

Step-by-step explanation:

We want to use a 0.01 significance level to test the claim that the rate of inaccurate orders is equal to 10%.

We set up our hypothesis to get:

$H_0:p=0.10$ ------->null hypothesis

$H_1:p\ne0.10$ ------>alternate hypothesis

This means that: $p_0=0.10$

Also, we have that, one restaurant had 36 orders that were not accurate among 324 orders observed.

This implies that: $\hat p=\frac{36}{324}=0.11$

The test statistics is given by:

$z=\frac{\hat p-p_0}{\sqrt{\frac{p_0(1-p_0)}{n} } }$

We substitute to obtain:

$z=\frac{0.11-0.1}{\sqrt{\frac{0.1(1-0.1)}{324} } }$

This simplifies to:

$z=0.6$

We need to calculate our p-value.

P(z>0.6)=0.2743

Since this is a two tailed test, we multiply the probability by:

The p-value is 2(0.2723)=0.5486

Since the significance level is less than the p-value, we fail to reject the null hypothesis.

We do not have sufficient evidence to reject the claim that ,the rate of inaccurate orders is equal to 10%.

3 0

3 years ago

H-5.3=2.6 solve the equation

Alex

The answer should be H= 7.9

7 0

2 years ago

Albert has $105 to spend on new basketball shoes. On his favorite shoe website, the prices for a pair of the shoes range from $8

STatiana [176]

Scenario 1

It is given that on Albert's favorite shoe website, the prices for a pair of the shoes range from $80 to $180 and the delivery fee is one-twentieth of the price of the basketball shoes.

We know that Albert has $105 to spend on new basketball shoes.

From the above pieces of information we see that the minimum that Albert will have to spend is $80+\frac{1}{12}\times 80=80+6.67=86.67$ dollars.

Now, we know that Albert can spend a maximum of $105 including the delivery fee. Let the upper limit of the price of the shoe Albert can buy be $x$ . So, the upper limit of the domain can be found as: