Answer:
Area of shaded part ABCEF = 66 sq.cm
Step-by-step explanation:
AB = 8cm
CD = 8cm
Let DE = x cm
CE = 3x cm
CD = CE + DE = 8cm
x + 3x = 8
4x = 8
x = 8/4 = 2 cm
DE = 2cm
CE = 3 * 2 = 6 cm
Area of triangle ADE = 1/2 * base * height
= 1/2 * DE * AD
= 1/2 * 2 * 11 = 11 sq. cm
Area of triangle AEF = Area of triangle ADE = 11 sq. cm
Area of Rectangle ABCD = l * b = 8 * 11 = 88 sq.cm
Area of shaded part ABCEF = Area of Rectangle ABCD - (Area of triangle AEF + Area of triangle ADE)
= 88 - ( 11 + 11 ) = 88 -22 = 66 sq.cm
Answer:
<u>brainliest plzzzzzzzz</u>
120
Step-by-step explanation:
LCM=1320
(GDC) HCF=12
Another no.=132
let second no. be =A
According to question
First no.×Second no.=HCF×LCM
132×A=12×1320
132×A=15840
A=15840/132
A=120
Other no. is 120
Answer:
5
Step-by-step explanation:
6-6/7
using pemdas it's:
6/7= 0.857
6-0.857=5.143
5.143 to the nearest whole number is 5
Answer:
Approximately 3 grams left.
Step-by-step explanation:
We will utilize the standard form of an exponential function, given by:
In the case of half-life, our rate <em>r</em> will be 1/2. This is because 1/2 or 50% will be left after <em>t </em>half-lives.
Our initial amount <em>a </em>is 185 grams.
So, by substitution, we have:
Where <em>f(t)</em> denotes the amount of grams left after <em>t</em> half-lives.
We want to find the amount left after 6 half-lives. Therefore, <em>t </em>= 6. Then using our function, we acquire:
Evaluate:
So, after six half-lives, there will be approximately 3 grams left.
3*(18-13)
3* 5
15
The answer is 15
