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masya89 [10]
4 years ago
7

Which equation demonstrates the multiplicative identity property?

Mathematics
1 answer:
eduard4 years ago
8 0
Not A because that is addition, B is correct because the identity property of multiplication is multiplying something by 1,
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Several schools reported the number of students who received a flu vaccine in a year and number of cases of the flu amongst thei
Rom4ik [11]

Answer:

slope trend: - 1/4

y intercept : 85

Hope it Helps!

Step-by-step explanation:

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3 years ago
Show work please <br>*ill give brainliest<br><br>solve the equation for h.<br>S=LW+WH+HL
NISA [10]
Hey there, Brainiac!

To start this off, let's subtract LW from both sides of the equation.

S - LW = WH + HL

Now, let's use the distributive property on WH+HL.
Using the distributive property, we can change that to H(W+L)

S - LW = H(W+L)

Now, to finish this off, let's divide both sides by (W+L)

\frac{S-LW}{W+L} = H

That's your answer.

Have an awesome day! :)

~collinjun0827, Junior Moderator
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3 years ago
Make a 10 or 100 to subtract mentally 76_59
Sliva [168]
17 is the answer. Hope i could help!
Thunderclan89
8 0
3 years ago
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Is this correct?<br><br>A.yes <br><br>B. No<br><br>C. Maybe<br><br>D. I DUNNO???!!!
Mamont248 [21]

Answer:

its correct there adding to or subtracting 2 each time.

Step-by-step explanation:

6 0
2 years ago
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The warranty for a particular system on a new car is 2 years. During which there is no limit to the number of warranty claims pe
const2013 [10]

Answer: by using Poisson distribution

The warranty for a particular system on a new car is 2 years

P(x=2)= 0.143

There is no limit to the number of warranty claims per car

P(X=0) = 0.449

Step-by-step explanation:

<u>step:-1</u>

A random variable X is said to follow a Poisson distribution if it assumes only non-negative values and its probability distribution is given by

P(X=x) = \frac{e^{-w}w^{x}  }{x!}

here w>0 is called the parameter of the distribution

<u>Step 2</u>:- Given mean value of Poisson distribution = 0.8

The warranty for a particular system a new car is 2 years

P(X=x)=P(X=2)=\frac{e^{-0.8}{0.8^{2} }  }{2!}

P(x=2)= 0.143

<u>Step 3</u>:-

Given mean value of Poisson distribution = 0.8

There is no limit to the number of warranty claims per car

P(X=x)=P(X=0)=\frac{e^{-0.8}{0.8^{0} }  }{0!}

P(X=0) = 0.449

7 0
3 years ago
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