Answer: eyyyyyy my name is Jan what a coincidence
Step-by-step explanation:
Answer:
Kate did 15/8 part more than that of John.
Step-by-step explanation:
Given that,
John did 3 3/4 of his homework while Kate did 1 7/8 of her homework.
We need to find how much more of their homework did Kate do than John. It can be calculated as follows :
3 3/4 = 15/4
and
1 7/8 = 15/8
So,
Difference,

So, the required answer is 15/8.
I'm not sure what your saying but x is less or greater than b
Using two unit multiplier 628 km is equal to 62800000 cm
<u>Solution:</u>
628 kilometer to centimeter
We will go from kilometers to meters to centimeters.
Start by putting 628 km over 1:

We want to get rid of km and bring in m.
We know that 1000 m = 1 km.
Since km is in the numerator, we will make the first unit multiplier by putting 1 km in the denominator and 1000 m in the numerator, so the km will cancel. So we multiply by the unit multiplier,

Now the km's will cancel:

Now we want to get rid of m and bring in cm.
We know that 100 cm = 1 m.
Since meter is in the numerator, we will make the first unit multiplier by putting 1 meter in the denominator and 100 cm in the numerator, so the meter's will cancel. So we multiply by the unit multiplier


We cancel the m's and we end up with:

= 62800000 cm
Thus 628 km is equal to 62800000 cm
Answer:
14,062.5ft^2
Step-by-step explanation:
A farmer has a given length of fencing. Since this fencing is used to enclose a rectangular area, before it is then divided it into four pens using the same provided fencing material. This will definitely lead to five lengths of fencing which come along one side of the rectangle to form four pens.
Let us assume that the length of the each of the five sides be xft.
Then let the length of each of the two sides in the be yft.
Since the total length of fencing available is 750 feet.
Then we can have an equation of such:
5x+2y=750
Making y the subject
2y = 750-5x
y = 750-5x/2. ........1
The area of the rectangular region is given by:
A = xy. ......... 2
Combining (1) in (2) to find the area
A(x)= x. (750−5x)/2
=750x−5x^2/2 ........... (*)
Going by the means of first diffential calculus.
A(x)=750x−5x^2/2
A'(x) = 750-10x/2
Setting A'(x) = 0
750-10x/2 = 0
750-10x = 2×0
750-10x = 0
750= 10x
x = 750/10
x = 75
Now that we have x = 75
We can now substitute into equation (*)
A(x) = 750×75-5×75^2/2
= (56250-28125)/2
= 28126/2
= 14062.5
Hence the rectangular region of maximum area is
14062.5ft^2