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3 years ago

I need help please!!!

Mathematics

1 answer:

Jlenok [28]3 years ago

7 0

Answer:

1. Explain what a medical sociologist means by "health and illness are social attributes influenced by social factors"

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38 anyone??? I need help

pantera1 [17]

A: for every foot you will divide by 9 feet.
B: divide 15 by 9

8 0

3 years ago

The volume of the crate is 72 cubic feet but the length is 3ft the base is 6ft and the height is unknown

k0ka [10]

The volume of a crate is b x l x h. Reverse it to get 3 times 6 times h = 72. 3 times 6 is 18, so you know 18h=72. Divide both sides by 18 to get h = 4 ft.

3 0

3 years ago

Can someone help me on this

Sidana [21]

Answer:

Area = 702.9 or 703

Step-by-step explanation:

By Pythagoras the. first, we need to find the base!

(H)2 = (P)2 + (B)2

(82)2 = (18)2 + b2

6724 = 324 + b2

b2 = 6724-324

b2 = 6100

b = √6100

b = 78.1

note - they all are in square

Now, area of the triangle:-

1/2 * b * h

1/2 * 78.1 * 18

= 702.9

Hope it helps!

6 0

3 years ago

Read 2 more answers

For the problem 1/5g- 1/10- g + 1 3/10g -1/10, Tyson created an equivalent expression using the following steps. 1/5g+-1g+1 3/10

professor190 [17]

The true statements are:

Tyson's expression is not equivalent to the original expression
The equivalent expression is: $\frac{1}{2}g- \frac 1{5}$

<h3>What are equivalent expressions?</h3>

Equivalent expressions are expressions that have equal values

The original expression is given as:

$\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10}$

Collect like terms

$\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10} = \frac 15g - g + 1 \frac{3}{10}g- \frac 1{10} -\frac{1}{10}$

Evaluate the like terms

$\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10} = \frac{1}{2}g- \frac 1{5}$

Tyler's equivalent expression is given as:

$\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10}$

Collect like terms

$\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10} = \frac15g-g+ 1 \frac3{10}g-\frac 45g-\frac 1{10}+1 \frac{1}{10}$

Evaluate the like terms

$\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10} = -\frac 3{10}g$

The simplified expressions of the original expression, and Tyson's equivalent expressions are not equal.

Hence, Tyson's expression is not equivalent to the original expression

Read more about equivalent expressions at:

brainly.com/question/9603710

3 0

2 years ago

Help me find the area please

TiliK225 [7]

9 x 3 = 27
27/9=3

12 x 3= 36
36/3=12
ANSWER: 36cm^2

5 0

3 years ago

Read 2 more answers