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777dan777 [17]
3 years ago
6

Someone please help Ik in desperate need

Mathematics
1 answer:
nikklg [1K]3 years ago
3 0

Answer:

hiiii can i get a closer look

Step-by-step explanation:

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Find the product of 4x 4 and enter it in the space provided. Notice that a
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Answer:

16

Step-by-step explanation:

4+4=8

8+8=16

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A train leaves Buffalo traveling west at 60 miles per hour. An hour later, another train leaves Buffalo traveling east at 80 mil
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Consider the polynomial equation x(x - 3)(x + 6) (x-7) -0. Which of the following are zoros of the
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Answer:

The zeros are : 0, 3, -6, 7.

Step-by-step explanation:

Zeros of a polynomial is the values at which the polynomial becomes zero. They are also called the roots of the polynomial.

When (x - a)(x - b) = 0, we can say that either (x - a) = 0 or (x - b) = 0. At least one zero renders the whole equation to be zero.

Now, we are given that: x. (x - 3). (x + 6). (x - 7) = 0

⇒ To make the equation zero, at least one of the following should be true:

x = 0

x - 3 = 0  ⇒ x = 3

x + 6 = 0 ⇒ x = -6

x - 7 = 0 ⇒  x = 7

Therefore, x can take any one of the above values and that would make the polynomial zero.

4 0
3 years ago
URGENT HELP PLEASE!
Vaselesa [24]

Answer:

(a) x=\dfrac{\pi}{8},\dfrac{3\pi}{8},\dfrac{9\pi}{8},\dfrac{11\pi}{8}

(b) x=\dfrac{3\pi}{2},\dfrac{\pi}{6},\dfrac{5\pi}{6}

Step-by-step explanation:

It is given that 0\leq x\leq 2\pi.

(a)

\sqrt{2}\sin 2x=1

\sin 2x=\dfrac{1}{\sqrt{2}}

\sin 2x=\dfrac{\pi}{4}

2x=\dfrac{\pi}{4},\dfrac{3\pi}{4},\dfrac{9\pi}{4},\dfrac{11\pi}{4}     [\because \sin x=\sin y\Rightarrow x=n\pi+(-1)^ny]

x=\dfrac{\pi}{8},\dfrac{3\pi}{8},\dfrac{9\pi}{8},\dfrac{11\pi}{8}

(b)

\csc^2 x-\csc x-2=0

\csc^2 x-2\csc x+\csc x-2=0

\csc x(\csc x-2)+1(\csc x-2)=0

(\csc x+1)(\csc x-2)=0

\csc x=-1\text{ or }\csc x=2

\sin x=-1\text{ or }\sin x=\dfrac{1}{2}         [\because \sin x=\dfrac{1}{\csc x}]

x=\dfrac{3\pi}{2}\text{ or }x=\dfrac{\pi}{6},\dfrac{5\pi}{6}

Therefore, x=\dfrac{3\pi}{2},\dfrac{\pi}{6},\dfrac{5\pi}{6}.

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