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koban [17]
3 years ago
8

Which expression is equivalent to: (x^1/4 y^16)^1/2 ?

Mathematics
1 answer:
Rainbow [258]3 years ago
3 0

Answer: B. X^1/8 Y^8

Step-by-step explanation:


You might be interested in
Suppose that we don't have a formula for g(x) but we know that g(3) = −5 and g'(x) = x2 + 7 for all x. (
True [87]
So it tells us that g(3) = -5 and g'(x) = x^2 + 7.

So g(3) = -5 is the point (3, -5)
Using linear approximation
g(2.99) is the point (2.99, g(3) + g'(3)*(2.99-3))

now we just need to simplify that
(2.99, -5 + (16)*(-.01)) which is (2.99, -5 + -.16) which is (2.99, -5.16)
So g(2.99) = -5.16 

Doing the same thing for the other g(3.01)
(3.01, g(3) + g'(3)*(3.01-3))
(3.01, -5 + 16*.01) which is (3.01, -4.84)
So g(3.01) = -4.84

So we have our linear approximation for the two. 

If you wanted to, you could check your answer by finding g(x).  Since you know g'(x), take the antiderivative and we will get 
g(x) = 1/3x^3 + 7x + C
Since we know g(3) = -5, we can use that to solve for C
1/3(3)^3 + 7(3) + C = -5 and we find that C = -35
so that means g(x) = (x^3)/3 + 7x - 35

So just to check our linear approximations use that to find g(2.99) and g(3.01)

g(2.99) = -5.1597
g(3.01) = -4.8397

So as you can see, using the linear approximation we got our answers as
g(2.99) = -5.16
g(3.01) = -4.84
which are both really close to the actual answer.  Not a bad method if you ever need to use it. 
5 0
3 years ago
In a group of 60 students, 18 students take algebra i, 20 students take algebra ii, and 10 students take both subjects. how many
nadya68 [22]

Answer:

  32

Step-by-step explanation:

The number that take algebra i includes those who take both subjects, as does the number taking algebra ii. Then the number taking algebra i alone is ...

   18 -10 = 8 . . . . . take only algebra i

So the number taking any kind of algebra is ...

  20 + 8 = 28

and the number not taking either subject is ...

  60 -28 = 32 . . . not taking either subject

8 0
3 years ago
Find the domain for each expression. (1/x)+5<br> 1/x<br> X+5/x+5<br> X^2/x<br> 7/(x-2)
wel

Using it's concept, it is found that the domain for the expressions is, respectively, given by:

x \neq 0, x \neq 0, (-\infty, \infty), (-\infty, \infty), x \neq 2

<h3>What is the domain of a function?</h3>

It is the <u>set that contains all possible input values</u>.

In a fraction, the denominator cannot be zero, hence:

  • The domain of the first two expressions is of x \neq 0.
  • The domain of the last expression is of x \neq 2.

The third expression can be simplified, as:

(x + 5)/(x + 5) = 1.

The same is true for the fourth, as:

x²/x = 1.

Neither has any restriction, hence their domain is all real numbers, represented by (-\infty, \infty).

More can be learned about the domain of a function at brainly.com/question/25897115

6 0
2 years ago
The height of a cylinder is equal to the diameter of the base What expression represents the volume of the cylinder, in cubic un
Sveta_85 [38]

Answer: 3 units

Step-by-step explanation:

the volume of a cone C = πr²h/3

C = 18π, h =2x, r = diameter/2 = 2x/2 =x

18π = π* x²* 2x/3

divide through by π

18 = x² * 2x/3

multiply through by 3

54 = 2x³

divide through by 2

27 = x³

x =∛27 = 3

x = 3 units = radius

4 0
4 years ago
Hey guys ♡
Marat540 [252]

Answer:

m = - 31

Step-by-step explanation:

Given

\frac{m-1}{2} - \frac{m-2}{3} = \frac{m-4}{7}

Multiply through by 42 , the LCM of 2, 3 and 7 , to clear the fractions

21(m - 1) - 14(m - 2) = 6(m - 4) ← distribute parenthesis

21m - 21 - 14m + 28 = 6m - 24

7m + 7 = 6m - 24 ( subtract 6m from both sides )

m + 7 = - 24 ( subtract 7 from both sides )

m = - 31

4 0
3 years ago
Read 2 more answers
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