A.) To find the maximum height, we can take the derivative of h(t). This will give us the rate at which the horse jumps (velocity) at time t.
h'(t) = -32t + 16
When the horse reaches its maximum height, its position on h(t) will be at the top of the parabola. The slope at this point will be zero because the line tangent to the peak of a parabola is a horizontal line. By setting h'(t) equal to 0, we can find the critical numbers which will be the maximum and minimum t values.
-32t + 16 = 0
-32t = -16
t = 0.5 seconds
b.) To find out if the horse can clear a fence that is 3.5 feet tall, we can plug 0.5 in for t in h(t) and solve for the maximum height.
h(0.5) = -16(0.5)^2 + 16(-0.5) = 4 feet
If 4 is the maximum height the horse can jump, then yes, it can clear a 3.5 foot tall fence.
c.) We know that the horse is in the air whenever h(t) is greater than 0.
-16t^2 + 16t = 0
-16t(t-1)=0
t = 0 and 1
So if the horse is on the ground at t = 0 and t = 1, then we know it was in the air for 1 second.
Multiply her monthly payment by the number of months she paid so far:
567 x 48 = 27,216 paid so far.
Now add the amount she still owes:
27,216 + 1,250 = $28,466 total price.
Answer:
Percentage change in interest groups between 1959 (500) & 1995 (600) = 20%
Step-by-step explanation:
Percentage change = <u>Change ie (New - Old) </u> x 100
Old value
Suppose -
Number of interest groups in 1959 = 500
Number of interest groups in 1995 = 600
Percentage change = [ (600 - 500) / 500 ] x 100
( 100 / 500 ) x 100 = 20%
Answer:
3rd one
Step-by-step explanation:
2l + 2w = P
2w = P - 2l
w = P - 2l / 2
Total price after 6 years in Account I is :
Total price after 6 years in Account II is :
Total balance, 
Hence, this is the required solution.
