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RideAnS [48]
3 years ago
9

The life span of a species of fruit fly have a bell-shaped distribution, with a mean of 33 days and a standard deviation of 4 da

ys.
What percentage corresponds to the life span of fruit flies that are between 29 days and 37 days?
Mathematics
1 answer:
liq [111]3 years ago
3 0

Answer:

68.26% corresponds to the life span of fruit flies that are between 29 days and 37 days

Step-by-step explanation:

Given that the life span of a species of fruit fly have a bell-shaped distribution, with a mean of 33 days and a standard deviation of 4 days.

Let X be the life span

X is N(33,4)

we can convert X into Z standard normal variate by

z=\frac{x-33}{4}

To find the percentage  corresponds to the life span of fruit flies that are between 29 days and 37 days

For this let us find probability for x lying between 29 and 37 days

29\leq x\leq 37\\=-1\leq z\leq 1

Probability = P(|z|<1) = 0.6826

Convert to percent

68.26% corresponds to the life span of fruit flies that are between 29 days and 37 days

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<em>Additional comment</em>

Of course, the subtraction property of equality comes into play, also. For some unknown, X, you have (in both cases) ...

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