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Radda [10]
3 years ago
8

Angle P and angle Q are supplementary. Angle P measures 5x and angle Q measures 3x – 12. Find the measure of angle P.

Mathematics
2 answers:
NNADVOKAT [17]3 years ago
5 0

Two angles are called supplementary angles if the sum of two angles is 180 degrees and they form a linear pair.

Here we are given than angle P and angle Q are supplementary angles.

Sum of angle P and angle Q will be 180.

Angle P measures 5x and angle Q measures 3x – 12

Adding the two angles,

5x+(3x-12) =180

8x-12=180

8x=180+12

8x=192

x=24

Angle P = 5x

Angle P =5*24 =120

Answer: Angle P is 120 degrees.



Lady_Fox [76]3 years ago
3 0
X will equal 25 that should give you a hint
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There are 7800 grams of lodine that have a half-life of 8 days. How much lodine will remain after 40 days?
anygoal [31]

Given that we know the initial mass of Iodine and its half-life, we want to see how much will remain after 40 days.

After 40 days, 244.17 grams of Iodine will remain.

<h3 /><h3>The half-life of materials and how to use it:</h3>

The half-life of a material is the time it takes for that amount of material to reduce to its half.

We can model the amount of Iodine as:

A(t) = A*e^{k*t}

  • Where A is the initial amount, in this case, 7800g.
  • k is a constant that depends on the half-life.
  • t is the time in days.

Replacing what we know, we get:

A(t) = 7800g*e^{k*t}

Now we use the fact that the half-life is 8 days, this means that:

e^{k*8} = 1/2

ln(e^{k*8}) = ln(1/2)

k*8 = ln(1/2)

k = ln(1/2)/8 = -0.0866

Then the function is:

A(t) =  7800g*e^{-0.0866*t}

So now we just need to evaluate this in t = 40.

A(40) = 7800g*e^{-0.0866*40} = 244.17g

So, after 40 days, 244.17 grams of Iodine will remain.

If you want to learn more about half-life and decays, you can read:

brainly.com/question/11152793

3 0
2 years ago
Plz help ASAP and good explanation thank you
PilotLPTM [1.2K]
10 + 43 - 5 = 48

5^2 = 25

48/6 = 7

7 + 25 = 32

Answer 32
3 0
3 years ago
The answer or what measurements I need to multiply?
Zigmanuir [339]
Spilt into two figures
first one = 10 x 8 x 14 = 1120
second one = 10 x 10 x 8 = 800
Total volume = 1120 + 800 = 1920 cubic cm
6 0
3 years ago
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