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3 years ago

Find the value of two numbers if their sum is 12 and their difference is 4. Show work please.

Mathematics

2 answers:

Elza [17]3 years ago

6 0

Answer:

8,4

Step-by-step explanation:

x+y=12

x-y=4

(x+y)(x-y)=12*4

x^2-y^2=48

x=8 y=4

Irina18 [472]3 years ago

5 0

Answer:

4 & 8

Step-by-step explanation:

x-y = 4 -> x = 4+y

x+y = 12 = 4+y+y -> 4+2*y = 12

-> 2*y = 8 -> y = 4

-> x = 4+y = 8

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(2x^3+6x-1)+(3x^2-7x)

sattari [20]

For this case we must simplify the following expression:

$(2x ^ 3 + 6x-1) + (3x ^ 2-7x)$

We eliminate the parentheses taking into account that:

$+ * + = +\\+ * - = -$

So, we have:

$2x ^ 3 + 6x-1 + 3x ^ 2-7x =$

We add similar terms taking into account that:

Different signs are subtracted and the sign of the major is placed:

$2x ^ 3 + 3x^2-x-1$

Answer:

$2x ^ 3 + 3x^2-x-1$

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Nesterboy [21]

Answer:

Step-by-step explanation:

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olga nikolaevna [1]

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AVprozaik [17]

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3 years ago

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BlackZzzverrR [31]

Answer:

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Step-by-step explanation:

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