The slope is 1/1
You can use rise over run
Answer:
The length of the hypotenuse is 16.2 inches.
Step-by-step explanation:






Answer:
0.0816
Step-by-step explanation:
You got 21 papers on Monday. Because if you add 3 7 times it equals 21.
Hope it is correct!

has critical points where the derivative is 0:

The second derivative is

and
, which indicates a local minimum at
with a value of
.
At the endpoints of [-2, 2], we have
and
, so that
has an absolute minimum of
and an absolute maximum of
on [-2, 2].
So we have


