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choli [55]
2 years ago
6

How to solve using perfect square x^2-4x-32=0

Mathematics
1 answer:
zmey [24]2 years ago
5 0
Perfect\ square:(a-b)^2=a^2-2ab+b^2\\\\x^2-4x-32=0\ \ \ \ |add\ 32\ to\ both\ sides\\\\x^2-4x=32\\\\x^2-2x\cdot2=32\ \ \ \ |add\ 2^2\ to\ both\ sides\\\\x^2-2x\cdot2+2^2=32+2^2\\\\(x-2)^2=32+4\\\\(x-2)^2=36\iff x-2=-\sqrt{36}\ or\ x-2=\sqrt{36}\\\\x-2=-6\ or\ x-2=6\ \ \ \ |add\ 2\ to\ both\ sides\\\\\boxed{x=-4\ or\ x=8}
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-1/6 + 2/3 ( 9 + - 3/4) + - 1/2
Liono4ka [1.6K]
First simplify the section in the parenthesis. 
-1/6 + 2/3(8 1/4) + -1/2 
Then multiply 2/3 by 8 1/4.
-1/6 + 5 1/2 + -1/2 
Add -1/2 to 5 1/2. 
-1/6 + 5 
Add 5 to -1/6. 
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Which angle is congruent to p
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...........................
cupoosta [38]

Answer:

3/5 or 0.6

Step-by-step explanation:

Here, given the value of tan theta , we want to find the value of sine theta

Mathematically;

tan theta = 0pposite/adjacent

Sine theta = opposite/hypotenuse

Firstly we need the length of the hypotenuse

This can be obtained using the Pythagoras’ theorem which states that the square of the hypotenuse equals sum of the squares of the two other sides.

Let’s call the hypotenuse h

h^2 = 3^2 + 4^2

h^2 = 9 + 16

h^2 = 25

h = √(25)

h = 5

Now from the tan theta, we know that the opposite is 3

Thus, the value of the sine theta = 3/5 or simply 0.6

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