No---------------------------------
If a set covers a range of points, including those between isolated points and can not be written as a list, it is called continuous set. Continuous set are not restricted to defined separate values, they can occupy any value over a continuous range.
Answer:
0.5<2-√2<0.6
Step-by-step explanation:
The original inequality states that 1.4<√2<1.5
For the second inequality, you can think of 2-√2 as 2+(-√2).
Because of the "properties of inequalities", we know that when a positive inequality is being turned into a negative, the numbers need to swap and become negative. So, the original inequality becomes -1.5<-√2<-1.4. (Notice how the √2 becomes negative, too). This makes sense because -1.5 is less than -1.4.
Using our new inequality, we can solve the problem. Instead of 2+(-√2), we are going to switch "-√2" with both possibilities of -1.5 and -1.6. For -1.5, we would get 2+(-1.5), or 0.5. For -1.4, we would get 2+(-1.4), or 0.6.
Now, we insert the new numbers into the equation _<2-√2<_. The 0.5 would take the original equation's "1.4" place, and 0.6 would take 1.5's. In the end, you'd get 0.5<2-√2<0.6. All possible values of 2-√2 would be between 0.5 and 0.6.
Hope this helped!
Answer:
-4r²-3s²
Step-by-step explanation:
Remove unnecessary parentheses:
r²+s²-(5r²+4s²)
Connect like terms:
-4r²+s²-4s²
Simplify/ collect like terms:
-4r²-3s²
Solution:
-4r²-3s²
Answer:
B: |8| + (-7)
Step-by-step explanation:
When you are looking for the distance between two numbers, always add. The distance between 8 and -7 is 15 (|8| = 8). If, for instance, the answer was negative, which it is now, just find the absolute value of -15 which equals 15. The answer is B.
