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Blababa [14]
3 years ago
11

Plsss help me!!!!

Mathematics
1 answer:
m_a_m_a [10]3 years ago
7 0

Answer:

The answer to your problem is 10

Step-by-step explanation:

tony is 5 years younger than Marvin's age 1 year from now.

t = (m+1) - 5

t = m - 4

6 years ago tony was half as old as marvin was then.

t - 6 = 1/2(m - 6)

Get rid of the fraction, multiply both sides by 2

2(t-6) = m - 6

2t - 12 = m - 6

2t = m - 6 + 12

2t = m + 6

from the first statement, replace t with (m-4)

2(m-4) = m + 6

2m - 8 = m + 6

2m - m = 6 + 8

m = 14 is Marvin's present age

:

how old is tony now?

t = 14 - 4

t = 10 yrs is tony's age

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Calculate limits x&gt;-infinity<br> -2x^5-3x+1
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Given:

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\lim_{x\to -\infty}(-2x^5-3x+1)

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Solution:

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