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Blababa [14]
3 years ago
11

Plsss help me!!!!

Mathematics
1 answer:
m_a_m_a [10]3 years ago
7 0

Answer:

The answer to your problem is 10

Step-by-step explanation:

tony is 5 years younger than Marvin's age 1 year from now.

t = (m+1) - 5

t = m - 4

6 years ago tony was half as old as marvin was then.

t - 6 = 1/2(m - 6)

Get rid of the fraction, multiply both sides by 2

2(t-6) = m - 6

2t - 12 = m - 6

2t = m - 6 + 12

2t = m + 6

from the first statement, replace t with (m-4)

2(m-4) = m + 6

2m - 8 = m + 6

2m - m = 6 + 8

m = 14 is Marvin's present age

:

how old is tony now?

t = 14 - 4

t = 10 yrs is tony's age

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Answer:

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Step-by-step explanation:

The equations are:

x^2+4y^2=100\\4y-x^2=-20

Solving for x^2 of the 2nd equation and putting that in place of x^2 in the 2nd equation we have:

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The pairs would be

(6,4) & (-6,4)

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