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Andre45 [30]
3 years ago
5

Solve this equation by substitution y=3x-4

Mathematics
1 answer:
Andrej [43]3 years ago
6 0
Well, the slope of this equation is 3 and the y intercept is -4.
Hope this helps :)
Check it out :)
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A 6-pack of toilet paper costs $5.40.  A 12-pack of toilet paper costs $11.  Which package offers the best price per roll?​
igomit [66]

Answer: 6-pack.

Step-by-step explanation:

assuming there’s no tax, the 6-pack would offer the best price per roll.

for 12 rolls w/ the 6 pack it’d be 10.80 which divided by 12 is .9(0)a roll. Where as the 12 for 11 is roughly .91 . So the 6-pack is a better offer.

5 0
2 years ago
Ben needs to mix 1.5 cups of lemonade concentrate with 4 cups or water to make lemonade. He has 6 cups of concentrate. How much
lubasha [3.4K]

Answer:

<u>24</u>

Step-by-step explanation:

To get your answer, you need to multiply 1.5 and 6.

<u>1.5 x 6 = 9</u>

Then you multiply 4 and 6.

<u>4 x 6 = 24</u>

Which is your final answer.

<h3><em>I hope this helps you! Good Luck!</em></h3>
4 0
3 years ago
What dose composite mean?
Sveta_85 [38]
Adjective: Made up of various parts or elements
5 0
2 years ago
If <img src="https://tex.z-dn.net/?f=%20300cm%5E%7B2%7D%20" id="TexFormula1" title=" 300cm^{2} " alt=" 300cm^{2} " align="absmid
Artist 52 [7]
Check the picture below.  Recall, is an open-top box, so, the top is not part of the surface area, of the 300 cm².  Also, recall, the base is a square, thus, length = width = x.

\bf \textit{volume of a rectangular prism}\\\\&#10;V=lwh\quad &#10;\begin{cases}&#10;l = length\\&#10;w=width\\&#10;h=height\\&#10;-----\\&#10;w=l=x&#10;\end{cases}\implies V=xxh\implies \boxed{V=x^2h}\\\\&#10;-------------------------------\\\\&#10;\textit{surface area}\\\\&#10;S=4xh+x^2\implies 300=4xh+x^2\implies \cfrac{300-x^2}{4x}=h&#10;\\\\\\&#10;\boxed{\cfrac{75}{x}-\cfrac{x}{4}=h}\\\\&#10;-------------------------------\\\\&#10;V=x^2\left( \cfrac{75}{x}-\cfrac{x}{4} \right)\implies V(x)=75x-\cfrac{1}{4}x^3

so.. that'd be the V(x) for such box, now, where is the maximum point at?

\bf V(x)=75x-\cfrac{1}{4}x^3\implies \cfrac{dV}{dx}=75-\cfrac{3}{4}x^2\implies 0=75-\cfrac{3}{4}x^2&#10;\\\\\\&#10;\cfrac{3}{4}x^2=75\implies 3x^2=300\implies x^2=\cfrac{300}{3}\implies x^2=100&#10;\\\\\\&#10;x=\pm10\impliedby \textit{is a length unit, so we can dismiss -10}\qquad \boxed{x=10}

now, let's check if it's a maximum point at 10, by doing a first-derivative test on it.  Check the second picture below.

so, the volume will then be at   \bf V(10)=75(10)-\cfrac{1}{4}(10)^3\implies V(10)=500 \ cm^3

6 0
3 years ago
Simplify:<br><img src="https://tex.z-dn.net/?f=2%20%5Cfrac%7B1%7D%7B4%7D%283.5%29%20" id="TexFormula1" title="2 \frac{1}{4}(3.5)
V125BC [204]

9514 1404 393

Answer:

  7 7/8

Step-by-step explanation:

There are several ways to get there.

  2.25×3.5 = 7.875 = 7 7/8

  (2 1/4)(3 1/2) = (9/4)(7/2) = 63/8 = 7 7/8

  (2 1/4)(3.5) = 2(3.5) +(1/4)(3.5) = 7 + (2·3.5)/(2·4) = 7 +7/8 = 7 7/8

A typical graphing calculator will let you enter this problem directly, giving you a result either as a decimal, improper fraction, or a mixed number.

4 0
2 years ago
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