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4 years ago

Solve this equation by substitution y=3x-4

Mathematics

1 answer:

Andrej [43]4 years ago

6 0

Well, the slope of this equation is 3 and the y intercept is -4.
Hope this helps :)
Check it out :)

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Patricia got a 5/25 balloon mortgage and her initial payments were $965. She

erastovalidia [21]

Answer:

$390,900

Step-by-step explanation:

Given:

Initial payment = $965

New rapayment = $925 when she decided to refinance her ballon payment with a 30 year mortgage

In this case, a 5/25 ballon mortgage simply means loan repayment for the first 5 years is at a fixed rate.

Which means the total amount she paid in the first five years was=

12 * 5 * $965 = $57,900

When she refinanced the payment with a 30 year mortgage, her total payment = $925 * 12 * 30years = $333,000

Total financed cost Patricia paid =

$57,900 + $333,000 = $390,900

7 0

4 years ago

Given a slope of -6/7 and a y-intercept of -10, write the equation of the line in slope intercept form

Diano4ka-milaya [45]

The equation is:
$y=- \frac{6}{7}-10$

4 0

4 years ago

What is the period and midline?

OverLord2011 [107]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\

\end{array}\qquad$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{ A}}|\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\
\bullet \textit{vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\


\end{array}$

$\bf \begin{array}{llll}
\bullet \textit{function period}\\
\qquad \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\
\qquad \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}
$

so if you notice yours $\bf \begin{array}{llll}
3.2cos&\left( \frac{5}{3}\theta \right)+&6.1\\
&\ \uparrow&\uparrow \\
&B&D 
\end{array}$

now.. normally the function $\bf 3.2cos&\left( \frac{5}{3}\theta \right)$
has a D value of 0, or no vertical shift, and the amplitude and the period simply make the wave taller and thinner, but the midline is still the x-axis

now, with D = 6.1, that moves the midline up vertically that much

now.. the period, well, B = 5/3, normal period of cosine is $2\pi$
so, the new period will be $\bf \cfrac{2\pi }{B}\implies \cfrac{2\pi }{\frac{5}{3}}\implies \cfrac{6\pi }{5}$

notice the picture below
the vertical shift by the D component, or 6.1, moved the midline to y = 6.1 :)

6 0

3 years ago

Prove: AB is congruent to DC

attashe74 [19]

Answer:

AB and DE are congruent.

Step-by-step explanation:

Using alternate interior angles, they are congruent.

7 0

3 years ago

Which of the following is an arithmetic sequence?

mr_godi [17]

Answer:

222

Step-by-step explanation:

1114-5646

7 0

4 years ago