The answer is 54 square units.
let the vertex in quadrant I be (x,y)
<span>then the vertex in quadratnt II is (-x,y) </span>
<span>base of the rectangle = 2x </span>
<span>height of the rectangle = y </span>
<span>Area = xy </span>
<span>= x(27 - x</span>²<span>) </span>
<span>= -x</span>³<span> + 27x </span>
<span>d(area)/dx = 3x</span>²<span> - 27 </span><span>= 0 for a maximum of area </span>
<span>3x</span>²<span> = 3 x 3</span>² = <span>27 </span>
<span>x</span>²<span> = 9 </span>
<span>x = ±3 </span>
<span>y = 27-9 = 18 </span>
So, the largest area = 3 x 18 = 54 square units
Given :
The length of the rectangle, l = 8 cm/
The width of the rectangle, w = 75% of 8 cm


= 0.75 x 8
= 6
Therefore, the width of the rectangle is 6 cm.
Step-by-step explanation:

Hope this helps you.
Let me know if you have any other questions :-):-)
Answer:
8.5
Step-by-step explanation:
1.7*5=8.5