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Yuki888 [10]
2 years ago
10

According to the data released by the Chamber of Commerce of a certain city, the weekly wages of factory workers are normally di

stributed with a mean of $720 and standard deviation of $40. Find the probability that a worker selected at random from the city makes the following weekly wage. (Round your answers to four decimal places.)
Mathematics
1 answer:
stich3 [128]2 years ago
3 0

Complete question :

a. Of less than$720?

b. Of more than $840?

c. Between $680 and $760?

Answer:

0.500 ; 0.0013 ; 0.6827

Step-by-step explanation:

Given that :

Mean, μ = 720

Standard deviation, σ = 40

P(Z < x)

x = (x < 720)

Obtain the standardized value of x

P(x < 720) = (x - μ) / σ

P(x < 720) = (720 - 720) / 40

P(x < 720) = 0

P(Z < 0) = 0.5

B.) More than $840

P(x > 840)

P(x > 840) = (x - μ) / σ

P(x > 840) = (840 - 720) / 40

P(x > 840) = 120 / 40 = 3

P(Z > 3) = 0.0013499 (Z probability calculator)

c. Between $680 and $760?

P(760 < x < 680)

P(760 < x < 680) = ((x - μ) / σ) - ((x - μ) / σ)

P(760 < x < 680) = ((760 - 720) / 40) - (680 - 720) / 40)) = P( Z < - 1) - P(Z < - 1)

P(680 < x < 760) = 0.84134 - 0.15866 = 0.68268

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Answer:

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Step-by-step explanation:

Given in the question a quadratic equation,

−x² + 100x

To find the selling price, x, which will give highest revenue, y, we will find maximum value of parabola curve −x² + 100x

The value of -b/2a tells you the value x of the vertex of the function

−x² + 100x

here a = -1

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Selling price = -(100)/2(-1)

                    =   50

 

R = −(50)² + 100(50)

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3 years ago
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Mazyrski [523]

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33/36

Step-by-step explanation:

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3 years ago
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A box contain 12 balls in which 4 are white 3 are blue and 5 are red.3 balls are drawn at random from the box.find the chance th
Anastasy [175]

Answer:

3/11

Step-by-step explanation:

From the above question, we have the following information

Total number of balls = 12

Number of white balls = 4

Number of blue balls = 3

Number of red balls = 5

We solve this question using combination formula

C(n, r) = nCr = n!/r!(n - r)!

We are told that 3 balls are drawn out at random.

The chance/probability of drawing out 3 balls = 12C3 = 12!/3! × (12 - 3)! = 12!/3! × 9!

= 12 × 11 × 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1/(3 × 2 × 1) × (9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1)

= 220 ways

The chance of selecting 3 balls at random = 220

To find the chance that all the three balls are selected,

= [Chance of selecting (white ball) × Chance of selecting(blue ball) × Chance of selecting(red balls)]/ The chance/probability of drawing out 3 balls

Chance of selecting (white ball)= 4C1

Chance of selecting(blue ball) = 3C1 Chance of selecting(red balls) = 5C1

Hence,

= [4C1 × 3C1 × 5C1]/ 220

= 60/220

= 6/22

= 3/11

The chance that all three are selected is = 3/11

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3 years ago
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mrs_skeptik [129]

Question 1 :

x ≤ 4

Question 2:

i think its 40-5

7 0
2 years ago
Pls help, it’s worth 15 points!
babunello [35]
It’s option 1: 30 + 22i
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