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Let's define variables:
s = original speed
s + 12 = faster speed
The time for the half of the route is:
60 / s
The time for the second half of the route is:
60 / (s + 12)
The equation for the time of the trip is:
60 / s + 60 / (s + 12) + 1/6 = 120 / s
Where,
1/6: held up for 10 minutes (in hours).
Rewriting the equation we have:
6s (60) + s (s + 12) = 60 * 6 (s + 12)
360s + s ^ 2 + 12s = 360s + 4320
s ^ 2 + 12s = 4320
s ^ 2 + 12s - 4320 = 0
We factor the equation:
(s + 72) (s-60) = 0
We take the positive root so that the problem makes physical sense.
s = 60 Km / h
Answer:
The original speed of the train before it was held up is:
s = 60 Km / h
P = 2d
d = 2n.....n = 1/2d
q = d - 3
since dimes is mentioned in relation to quarters, pennies, and the nickels, u would use d as ur variable
ur expression would be : d + (2d) + (1/2d) + (d - 3) = total amount of coins...then u would solve for d, the number of dimes. And once u know that, u can sub that answer back into ur original equations to find the number of pennies, quarters and nickels
Answer:
horizontal translation of 9 units right and 2 units up
Step-by-step explanation:
I think this is right.
8/d^6
it needs to be 20 characters long so
