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podryga [215]
3 years ago
7

PLEASE HELP FOR 50 POINTS

Mathematics
1 answer:
ra1l [238]3 years ago
5 0

Answer:

what class are you in? if you have a book you can use this site called slader it gives you every answer for free and there is steps. HOPE THIS HELPS.

Step-by-step explanation:

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Bianca reads 3/4 of a page of a book each minute. She has 25 pages left to read. How many pages will she read in 5 1/2 minutes?​
Viktor [21]

Answer:

Bianca reads a page of a book in 1 ÷ (3/4) = 1 x (3/4) = 4/3 minutes;

We have 5 1/2 = 11/2 minutes;

She reads (11/2) ÷ (4/3) = (11/2) x (3/4) = 33 /8 = 4 1/8 pages;

Step-by-step explanation:

3 0
3 years ago
Write the equation of a line that is parallel to {y=-\dfrac{5}{4}x+7}y=− 4 5 ​ x+7y, equals, minus, start fraction, 5, divided b
AlladinOne [14]

Write the equation of a line that is parallel to y=-5/4x + 7

Any line parallel to the given line will have the same slope. In an equation presented in the y-intercept form, the slope is always the coefficient of "x". In this case, the slope is -5/4 (meaning the next point is down 5, and 4 to the right).


Our equation so far looks like this: y = -5/4x + b

"b" represents the y-intercept. To solve for be, we will need to substitute values into x and y. The next piece of information it gives us is one of the points, or solutions, of the line. This means that since this point is on the line, we can use its x and y values to substitute.


x = -4

y= 1

y = -5/4x + b

1 = -5/4(-4) + b

1 = 5 + b

-4 = b


Final Answer: y = -(5/4)x -4

7 0
3 years ago
Can someone please help me with this <br><br>which quadratic equation has two solutions or zeros​
ivann1987 [24]
It has to be the second one and it’s part of that answer or maybe it’s the third one
4 0
3 years ago
I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS AND EXPLAIN WHY THAT IS THE ANSWER
lubasha [3.4K]

Answer:

<em>13.1</em>  

Step-by-step explanation:

A = bh

~~~~~~~

b_{1} = 16 , h_{1} = 9

A = 16 × 9 = 144

From another side area of parallelogram  with hight "h" base "b"  

11h = 144

<em>h</em> = 144 ÷ 11 ≈ <em>13.1</em>

5 0
1 year ago
Find a particular solution to y" - y + y = 2 sin(3x)
leonid [27]

Answer with explanation:

The given differential equation is

y" -y'+y=2 sin 3x------(1)

Let, y'=z

y"=z'

\frac{dy}{dx}=z\\\\d y=zdx\\\\y=z x

Substituting the value of , y, y' and y" in equation (1)

z'-z+zx=2 sin 3 x

z'+z(x-1)=2 sin 3 x-----------(1)

This is a type of linear differential equation.

Integrating factor

     =e^{\int (x-1) dx}\\\\=e^{\frac{x^2}{2}-x}

Multiplying both sides of equation (1) by integrating factor and integrating we get

\rightarrow z\times e^{\frac{x^2}{2}-x}=\int 2 sin 3 x \times e^{\frac{x^2}{2}-x} dx=I

I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx -\int \frac{2\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx-\frac{2I}{3}\\\\\frac{5I}{3}=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{5}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{5} dx

8 0
2 years ago
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