Subtract the amount she has saved from the price of the laptop:
849 - 232 = 617
Now divide the amount she still needs by the amount she saves per week:
617 / 28 = 22.04
Because the answer has a number to the right of the decimal, she will need to save for 23 full weeks to have enough money.
If she saves for 22 weeks, she would be $1 short:
22 x 28 = 616 + 232 = 848
10>5h is an inequality that represents this. Don’t forget the line under the symbol! It shows possibly equal to. It’s not on my keyboard.
33.3 repeating
This can be simply found out by dividing 3.75 from 1.25
1.25 / 3.75 = .33
The LCD is basically the LCM of the denoenator so
to find LCM of exg 6 and 21, find factors and group
6=2 and 3 (one 2 and one 3)
21=3 and 7 (one 3 and one 7)
lcm=2 and 3 and 7 (include 6 and 21 in the number) (one 2 and one 3 and one 7)
LCM≈LCD
so
17.
denomenators are 2 and x^2
2=2
x^2=x times x
lcm=2 times x times x=2x^2
18.
denomenators are 6 and 9
6=2 and 3
9=3 and 3
LCM=2 times 3 times 3=18
19.
denomenators are z and 7z
z=z
7z=7 and z
lcm=7 times z=7z
20.
denomenators are 5b and 7b^3c
5b=5 and b
7b^3c=7 times b times b times b times c
LCM=7 times 5 times b times b times b times c=7b^3c=7cb^3
21. denomenator=5 and x+2
5=5
x+2=x+2
LCM=5 times (x+2)=5(x+2)=5x+10
22. denomenators are ab and b^2c
ab=a time b
b^2c=b times b times c
LCM=a times b times b times c=ab^2c=acb^2
23. demonenators are m+n and m-n
m+n=m+n
m-n=m-n
LCM=(m+n)(m-n)=m^2-n^2
24.denoenators are k and k^2-2
k=k
k^2-2=k^2-2
LCM=k times (k^2-2)=k^3-2k
