An experiment requires 62.7 g of ethyl alcohol (density = 0.790 g/mL). What volume, in liters, will be required?

Chemistry

2 answers:

jenyasd209 [6]4 years ago

4 0

Answer:

0.0794 L

Explanation:

An experiment requires 62.7 g of ethyl alcohol. The density of ethyl alcohol is 0.790 g/mL. The volume, in milliliters, corresponding to 62.7 g of ethyl alcohol is:

62.7 g × (1 mL/0.790 g) = 79.4 mL

1 liter is equal to 1000 milliliters. The volume, in liters, corresponding to 79.4 mL is:

79.4 mL × (1 L/ 1000 mL) = 0.0794 L

Brums [2.3K]4 years ago

3 0

Answer: 0.0794 L or 7.94x10-2L

Explanation:

Density is expressed by D= m/V mass over volume.

62.7 g / 0.790 g/mL = 79.4 mL

Convert this into L by dividing it to 1000. So the result is 0.0794 L

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ANTONII [103]

Answer: Option (a) is the correct answer.

Explanation:

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We calculate the azimutal numbers as follows.

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5 0

3 years ago

2a. Density is the relationship between mass and volume. Density has

Charra [1.4K]

The volume of copper : 3.24 ml

<h3>Further explanation </h3>

Density is a quantity derived from the mass and volume

Density is the ratio of mass per unit volume

With the same mass, the volume of objects that have a high density will be smaller than objects with a smaller type of mass

The unit of density can be expressed in g/cm³ or kg/m³

Density formula:

$\large{\boxed {\bold {\rho~=~ \frac {m} {V}}}}$