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Korolek [52]
3 years ago
12

The titration of 24.30 mL of HCl solution of unknown concentration requires 12.84 mL of a 0.120 M NaOH solution to reach the equ

ivalence point. What is the concentration of the unknown HCl solution in M?
Chemistry
1 answer:
Mnenie [13.5K]3 years ago
5 0

Answer:

0.0634 M HCl

Explanation:

Since HCl and NaOH react in a one-to-one mole ratio, we can just use M1V1 = M2V2 to solve for M1 (the concentration of HCl)

M1 = ? M HCl

V1 = 24.30 mL HCl

M2 = 0.120 M NaOH

V2 = 12.84 mL NaOH

M1(24.30 mL HCl) = (0.120 M NaOH)(12.84 mL NaOH)

M1 = 0.0634 M HCl

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What is the percent composition of N H S O in (NH4)2SO4
Lena [83]

Answer:

The percent composition is 21% N, 6% H, 24% S and 49% O.

Explanation:

1st) The molar mass of (NH4)2SO4 is 132g/mol, and it represents the 100% of the mass composition.

In 1 mole of (NH4)2SO4, there are:

- 2 moles of N.

- 8 moles of H.

- 1 mole of S.

- 4 moles of O.

2nd) It is necessary to calculate the mass of each element, multiplying its molar mass by the number of moles:

- 2 moles of N (14g/mol) = 28g

- 8 moles of H (1g/mol) = 8g

- 1 mole of S (32g/mol) = 32g

- 4 moles of O (16g/mol) = 64g

3rd) With a mathematical rule of three we can calculate the percent composition of each element in the molecule of (NH4)2SO4:

\begin{gathered} \text{ Nitrogen:} \\ 132g-100\% \\ 28g-x=\frac{28g*100\%}{132g} \\ x=21\% \end{gathered}\begin{gathered} \text{ Hydrogen:} \\ 132g-100\operatorname{\%} \\ 8g-x=\frac{8g*100\operatorname{\%}}{132g} \\ x=6\% \end{gathered}\begin{gathered} \text{ Sulfur:} \\ 132g-100\operatorname{\%} \\ 32g-x=\frac{32g*100\operatorname{\%}}{132g} \\ x=24\% \end{gathered}\begin{gathered} \text{ Oxygen:} \\ 100\%-21\%-6\%-24\%=49\% \\  \\  \end{gathered}

In this case, we can calculate the percent composition of Oxygen by subtracting the other percentages, since the total must be 100%.

So, the percent composition is 21% N, 6% H, 24% S and 49% O.

8 0
1 year ago
S<br> SIO₂ +3C Sic +20o<br> Sic ? mass in grams<br> С c-
seraphim [82]

Answer:

26.74g

Explanation:

The equation of the reaction is;

SIO₂ + 3C --> SiC +2CO

From the balanced equation, the relationship between SiC and C is;

3 mol of C produces 1 mol of SiC

Converting mol to mass using; Mass = moles * Molar mass

Mass of SiC = 1 mol * 40.11 g/mol = 40.11g

This means;

3 mol of C produces 40.11g of SiC

2 mol of C produces xg of SiC

3 = 40.11

2 = x

x = 2 * 40.11 / 3 = 26.74g

6 0
3 years ago
A scientist introduces an unknown type of particle into a cathode ray tube. The unknown particles travel in the same direction a
sergij07 [2.7K]

Answer: B

Explanation:

5 0
3 years ago
Using solubility rules, determine if the following compounds are soluble in water. insoluble soluble A. CuCl2 B. BaSO4
Leviafan [203]

Answer :

(A) CuCl_2 : It is soluble in water.

(B) BaSO_4 : It is insoluble in water.

Explanation :

Solubility : It is defined as the amount of solute dissolved in a solvent at a given temperature.

According to the solubility rules:

All chlorides are soluble except Ag^+,Pb^+\text{ and }Hg^{2+}

All sulfates are soluble except Ba^{2+},Pb^{2+},Ca^{2+}\text{ and }Sr^{2+}

From this we conclude that,

(A) CuCl_2 : It is soluble in water.

(B) BaSO_4 : It is insoluble in water.

8 0
4 years ago
Analiza a que se debe el cambio de color del papel tornasol rosa en presencia de un ácido.​
svp [43]

Answer:

El cambio ocurre a causa de que los iones reaccionan y producen un cambio en la disposición de los átomos que se encuentran presentes en el indicador.

5 0
3 years ago
Read 2 more answers
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