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mylen [45]
2 years ago
9

The _______________________________ css3 property can be used to create multiple columns of text within a single element.

Chemistry
1 answer:
tatuchka [14]2 years ago
4 0

The column count property can be used to create multiple columns of text within a single element.

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How many moles of KCIO3 most decompose to form 13.0 moles of potassium chloride?
Elden [556K]

Answer:

13 moles of KClO₃ will decompose to gives 13 moles of KCl.

Explanation:

Given data:

Moles of potassium chloride = 13.0 mol

Moles of KClO₃ = ?

Solution:

Chemical equation:

2KClO₃ → 2KCl + 3O₂

Now we will compare the moles of KCl  with KClO₃.

                     KCl         :           KClO₃

                      2            :             2

                      13           :            13

So 13 moles of KClO₃ will decompose to gives 13 moles of KCl.

6 0
4 years ago
How does the material of the bowl impact the temperature of the porridge?
madreJ [45]

Answer:

it depends on the material of the bowl. if the material is a good heat conductor, then it is a bad insulator vice versa.

6 0
3 years ago
Look at the picture and select the answer quicly
Mars2501 [29]
I believe c. I hope it helps :)
6 0
3 years ago
According to the following reaction, how many grams of chloric acid (HClO3) are produced in the complete reaction of 31.6 grams
gogolik [260]

Answer:

m_{HClO_3}=12.7gHClO_3

Explanation:

Hello,

Considering the reaction:

3Cl_2(g)+3H_2O(l)-->5HCl+HClO_3

The molar masses of chlorine and chloric acid are:

M_{Cl_2}=35.45*2=70.9g/mol\\M_{HClO_3}=1+35.45+16*3=84.45g/mol

Now, we develop the stoichiometric relationship to find the mass of chloric acid, considering the molar ratio 3:1 between chlorine and chloric acid, as follows:

m_{HClO_3}=31.6gCl_2*\frac{1molCl_2}{70.9gCl_2} *\frac{1molHClO_3}{3mol Cl_2} *\frac{85.45g HClO_3}{1mol HClO_3} \\m_{HClO_3}=12.7gHClO_3

Best regards.

4 0
4 years ago
What happens when aluminum fills its valence shell?
Andreyy89
ALUMINIUM CANT FILL ITS ORBITAL EXCEPT ITS REACT WITH OTHER ELEMENT SO WHAT HAPPENS IS THE ALUMINIUM IS NOW A COMPOUND
5 0
4 years ago
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