Speed / velocity (that's a slash) are always distance over time. divide 54 by 45
Answer:
197
Step-by-step explanation:
You have 6 sides of this object. So we will calculate six surface areas.
P1=5x5=25 ( on the top)
P2=9x5=45 ( on the bottom)
P3= 5x5= 25 (left side)
P4=6,4x5=32 (rightside)
P5= (9+5)x5/2=70/2=35 ( front trapeze)
P6=P5=35 ( behided trapeze)
P= p1+p2+p3+p4+p5+p6=
25+45+25+32+35+35 =197
Answer:
5
Step-by-step explanation:
cancel the common factor of 8
Answer:
Option D)Neither solution is extraneous.
Step-by-step explanation:
we have

we know that
two possible solutions are x=-7 and x=1
<u><em>Verify each solution</em></u>
Substitute each value of x in the expression above and interpret the results
1) For x=-7


----> is true
therefore
x=-7 is not a an extraneous solution
2) For x=1


----> is true
therefore
x=1 is not a an extraneous solution
therefore
Neither solution is extraneous
Answer:
Don't take my word for this but I think the max groups he can do is 16 because that is the lowest amount of marbles.
Step-by-step explanation: